We can eliminate choice C because our parabola is not upside down. The way I determined which one it was was by picking a point on the graph and testing the x value of the point in the equation. If the y value on the graph was the same as the y value on my calculator, then I chose the right one. Let me give you an example of what doesn't work first. Let's pick (3, 2) from the graph. Let's test that point in choice D. Filling in x = 3, y should = 2 if that's the right equation.

. Our y coordinate is not 7/2, it's 2. Let's try A:

. Again, our y value is 2, not -2. Let's try B:

. See how that works? Your choice is B.
Answer:
x = 4
Step-by-step explanation:
2 + 3(3x - 6) = 5(x - 3) + 15
Expand the parenthesis:
2 + 9x - 18 = 5x - 15 + 15
Simplify:
9x - 16 = 5x
Subtract 5x from both sides:
4x - 16 = 0
Add 16 to both sides:
4x = 16
Divide both sides by 4:
x = 4
Answer:
EG = 2 units
Step-by-step explanation:
Given that line q bisects EG at T , then
ET = TG ( substitute values )
x = x - 2 ( multiply through by 3 to clear the fraction )
x = 3x - 6 ( subtract x from both sides )
0 = 2x - 6 ( add 6 to both sides )
6 = 2x ( divide both sides by 2 )
3 = x
Then
ET =
x =
× 3 = 1
TG = x - 2 = 3 - 2 = 1
Thus
EG = ET + TG = 1 + 1 = 2 units
The first table, representing <em>f</em>(<em>x</em>), is linear. The data have a constant rate of change or slope:
<em />(between the first two points): <em>m</em> = (<em>y</em>₂ - <em /><em>y</em>₁)/(<em>x</em>₂ - <em>x</em>₁) = (22-18)/(-1--2) = 4/(-1+2) = 4/1 = 4. The rate of change between any two points is the same:
(between the last two points):<em> m</em> = (34-30)/(2-1) = 4/1 = 4.
The second table, representing <em>g</em>(<em>x</em>), is exponential. The data points are multiplied by the same constant between successive points. 2*2 = 4; 4*2= 8; 8*2 = 16, etc.
Answer:
22
Step-by-step explanation: