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Natali5045456 [20]
2 years ago
12

PLEASE HELP

Mathematics
1 answer:
Vladimir79 [104]2 years ago
8 0

For the given relation, the coefficient is (1/5) and the exponent is 1.

<h3 /><h3>Which are the coefficient and the exponent of the variable?</h3>

For a relation of the form:

y = a*x^n

a is the coefficient and n is the exponent.

In this case, we have:

y = \frac{x}{5}

This can be rewritten to:

y = \frac{1}{5}*x^1

So we can see that the coefficient is (1/5), and the exponent is 1.

If you want to learn more about exponents:

brainly.com/question/11975096

#SPJ1

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How do I solve these problems? ln(x) = 5.6 + ln(7.5) and log(x) = 5.6 - log(7.5)
SOVA2 [1]

Use the rules of logarithms and the rules of exponents.

... ln(ab) = ln(a) + ln(b)

... e^ln(a) = a

... (a^b)·(a^c) = a^(b+c)

_____

1) Use the second rule and take the antilog.

... e^ln(x) = x = e^(5.6 + ln(7.5))

... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents

... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms

... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)

2) Similar to the previous problem, except base-10 logs are involved.

... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.

... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5

... x ≈ 53,080.96

8 0
3 years ago
Help please what is the answer?
Dmitrij [34]
(pemdas), parenthesis then exponents.
7 * 2 = 14
14^ 7 = 105413504
8 0
3 years ago
The cost of a lack has increased by 30% to £65. Work out the original price
Sveta_85 [38]
Cost of lack increased by 30%

new cost of lack will be = 100% + 30% = 130%

We are given that new cost = £65

Thus 130% of original cost = 65

100% of original cost = 65 × 100/130 = £50

Thus original price was £50
7 0
3 years ago
Find the value of 14/8 + 15/12
n200080 [17]

Answer:

The value of <em> </em>\frac{14}{8} + \frac{15}{12}  = 3

Step-by-step explanation:

<u><em>Explanation</em></u>

<em>Given       </em>\frac{14}{8} + \frac{15}{12}<em></em>

<em></em>

<em>L.C.M     8 , 12   is  24</em>

<em>          </em>

<em>        </em>\frac{14}{8} + \frac{15}{12} = \frac{14 X 3 + 15 X 2}{24}<em></em>

<em>                   = </em>\frac{42 +30}{24} = \frac{72}{24} = 3<em></em>

<u><em>Final answer</em></u><em>:-</em>

The value of <em> </em>\frac{14}{8} + \frac{15}{12}  = 3

5 0
2 years ago
The value of a car x years from now is given by v(x) = 2000(0.75)x. What is the annual compound interest rate of depreciation?
patriot [66]
Hello! So because the value in the parenthesis is less than one, this represents exponential decay. 0.75 is 75% in decimal form. Percents are parts of 100. let's multiply that number from 100. 100 - 75 is 25. There. The rate of depreciation is 25%.
4 0
3 years ago
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