Use the rules of logarithms and the rules of exponents.
... ln(ab) = ln(a) + ln(b)
... e^ln(a) = a
... (a^b)·(a^c) = a^(b+c)
_____
1) Use the second rule and take the antilog.
... e^ln(x) = x = e^(5.6 + ln(7.5))
... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents
... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms
... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)
2) Similar to the previous problem, except base-10 logs are involved.
... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.
... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5
... x ≈ 53,080.96
(pemdas), parenthesis then exponents.
7 * 2 = 14
14^ 7 = 105413504
Cost of lack increased by 30%
new cost of lack will be = 100% + 30% = 130%
We are given that new cost = £65
Thus 130% of original cost = 65
100% of original cost = 65 × 100/130 = £50
Thus original price was £50
Answer:
The value of <em> </em>
= 3
Step-by-step explanation:
<u><em>Explanation</em></u>
<em>Given </em><em></em>
<em></em>
<em>L.C.M 8 , 12 is 24</em>
<em> </em>
<em> </em>
<em></em>
<em> = </em>
<em></em>
<u><em>Final answer</em></u><em>:-</em>
The value of <em> </em> = 3
Hello! So because the value in the parenthesis is less than one, this represents exponential decay. 0.75 is 75% in decimal form. Percents are parts of 100. let's multiply that number from 100. 100 - 75 is 25. There. The rate of depreciation is 25%.
