97.8-63.65
97.80
-63.65
-----------
34.15
10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit. This can be obtained by multiplying 10 with the tens digit and adding unit digit.
<h3>Which is the required expressions?</h3>
Given that, in a two digit number,
t = the tens digit
u = the ones digit
The expression for the digit will be ,
10×t + u = 10t + u
The value of its reversal,
u = the tens digit
t = the ones digit
10×u + t = 10u + t is the required expression
For example,
37 = 10×3 + 7 = 30 + 7 and its reverse 73 = 10×7 + 3 = 70 + 3
Hence 10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit.
Learn more about algebraic expressions here:
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Answer:
d=1.4
Step-by-step explanation:
cuz 10-1.4=8.6
Answer:
Bring 3x to the left: −3x + y = 2. Multiply all by −1: 3x − y = −2. Note: A = 3, B = −1, C = −2. This form: Ax + By + C = 0. is sometimes called "Standard Form", but is more properly called the "General Form".
Step-by-step explanation:
dat is only exsample so i thingk i help u
The value of the function (f.h)(x) is 96x⁵ + 132x⁴ + 78x³ + 18x²
<h3>How to solve function?</h3>
f(x) = 3x² + 4x³ + 8x⁴
g(x) = -3x + 12x² - 5x³
h(x) = 12x + 6
Therefore,
(f.h)(x) = f(x).h(x)
Hence,
f(x).h(x) = (3x² + 7x³ + 8x⁴)(12x + 6)
f(x).h(x) = 36x³ + 18x² + 84x⁴ + 42x³ + 96x⁵ + 48x⁴
(f.h)(x) = 96x⁵ + 84x⁴ + 48x⁴ + 36x³ + 42x³ + 18x²
(f.h)(x) = 96x⁵ + 132x⁴ + 78x³ + 18x²
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