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Korolek [52]
3 years ago
8

1/3log125/8-2log2/5+log80/125

Mathematics
1 answer:
morpeh [17]3 years ago
8 0

Answer:

3log2

Step-by-step explanation:

Given

\frac{1}{3} log( \frac{125}{8} ) - 2 log( \frac{2}{5} ) + log( \frac{80}{125} )

Required

Solve

Apply logarithm rules

log( \frac{125^{\frac{1}{3}}}{8^{\frac{1}{3}}} )- log( \frac{2^2}{5^2} ) + log( \frac{80}{125} )

log( \frac{5}{2}} )- log( \frac{4}{25} ) + log( \frac{80}{125} )

Apply quotient rule

log( \frac{5}{2} / \frac{4}{25} ) + log( \frac{80}{125} )

log( \frac{5}{2} * \frac{25}{4} ) + log( \frac{80}{125} )

log( \frac{100}{8} ) + log( \frac{80}{125} )

Apply product rule

log( \frac{100*80}{8*125} )

log( \frac{8000}{1000} )

log(8)

Express 8 as 2^3

log(2^3)

3log2

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Eddi Din [679]

Answer:

15 students

Step-by-step explanation:

The fraction of students who will repeat the exam is:

1-\frac{6}{9}

=\frac{9}{9} -\frac{6}{9} =\frac{3}{9}

simplified is:

\frac{1}{3}

Extract this fraction of 45:

45(\frac{1}{3} )=\frac{45}{3} =15

Hope this helps

5 0
2 years ago
If X is a normal random variable with parameters µ = 10 and σ 2 = 36, compute
alex41 [277]

Answer:

Step-by-step explanation:

Given that X is a normal random variable with parameters µ = 10 and σ 2 = 36,

X is N(10, 6)

Or z = \frac{x-10}{6}

is N(0,1)

a)  P(X > 5),

=P(Z>-0.8333)\\=0.7977

(b) P(4 < X < 16),

=P(|z|

(c) P(X < 8),

=P(Z

(d) P(X < 20),

=P(Z

(e) P(X > 16).

=P(Z>-0.6667)

= 0.2524

6 0
3 years ago
Kobina sells apple pies for 10gh each.kojo sells beverages for ghc1 each.if kobina sells 23 apple pies and kojo sells 17 beverag
sineoko [7]

Answer:

680

Step-by-step explanation:

Based on the given conditions, formulate:  17  × ( 23  + 17 )  

Calculate the sum or difference: 17  × 40  

Calculate the product or quotient: 680  

get the result: 680

Answer: 680

(Hope this helps can I pls have brainlist (crown)☺️)

7 0
3 years ago
according to the information that comes with a certain prescription drug, when taking this drug, there is a 24% chance of experi
sergij07 [2.7K]

There is 46% probability of experiencing neither of the side effects.

<h3>What is probability ?</h3>

Probability shows possibility to happen an event, it defines that an event will occur or not. The probability varies from 0 to 1.

Given that,

While taking drug, chances of experiencing nausea (n)= 24 %,

Chances of experiencing decreased sexual drive (d) = 46 %.

Also, there are 60% chances of experiencing both side effects.

Use vain diagram to solve this type of questions,

Total chances of experiencing side effects = 8 + 30 + 16 = 54

The chances of experiencing neither of the side effects = 100 - 54 = 46

So there is 46% probability of experiencing neither of the side effects.

To know more about Probability on:

brainly.com/question/12478394

#SPJ1

4 0
1 year ago
Evaluate 6t-2p-32u when t=6 and u = 1/46t - 20 - 32u when t = 6 and u = 1/4
Butoxors [25]

Answer:

8

Step-by-step explanation:

6(6)-20-32(1/4)

36-20-8

16-8

8

7 0
3 years ago
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