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Annette [7]
3 years ago
7

Help me please AS soon as possible please just this one question

Mathematics
1 answer:
andrew11 [14]3 years ago
5 0

Answer:

The largest side of given triangle is: AB

Step-by-step explanation:

In order to find the largest side, we have to find all the triangles first.

The two angles at point A will sum up to 180° as the angles on the straight line are supplementary.

So,

136 + Angle\ A = 180\\Angle\ A = 180-136 = 44

∠A = 44°

∠C = 71°

The sum of interior angles of a triangle is 180°

Using this:

∠A+∠B+∠C = 180°

44°+∠B+71° = 180°

∠B+115° = 180°

∠B = 180°-115°

∠B = 65°

In a triangle, the side opposite to the largest angle is the largest. In the given triangle, ∠C is the largest so the side AB which is opposite to ∠C is the largest.

Hence,

The largest side of given triangle is: AB

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statuscvo [17]

Answer: In a week you can travel 941 miles

Step-by-step explanation:

$240+0.15m=$381

Subtract $240 on both sides:

$240-$240+0.15m=$381-$240

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Divide 0.15 on both sides:

0.15m/0.15=141/0.15

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In a 3-digit number, the hundreds digit is one more than the ones digit and the tens digit is twice the hundreds digit. If the s
MaRussiya [10]

Answer:

The mentioned number in the exercise is:

  • <u>362</u>

Step-by-step explanation:

To obtain the mentioned number in the exercise, first you must write the equations you can obtain with it.

If:

  • x = hundredths digit
  • y = tens digit
  • z = ones digit

We can write:

  1. x = z + 1 (the hundreds digit is one more than the ones digit).
  2. y = 2x (the tens digit is twice the hundreds digit).
  3. x + y + z = 11 (the sum of the digits is 11).

Taking into account these data, we can use the third equation and replace it to obtain the number and the value of each digit:

  • x + y + z = 11
  • (z + 1) + y + z = 11 (remember x = z + 1)
  • z + 1 + y + z = 11
  • z + z +y + 1 = 11 (we just ordered the equation)
  • 2z + y + 1 = 11 (z + z = 2z)
  • 2z + y = 11 - 1 (we passed the +1 to the other side of the equality to subtract)
  • 2z + y = 10
  • 2z + (2x) = 10 (remember y = 2x)
  • 2z + 2x = 10
  • 2z + 2(z + 1) = 10 (x = z + 1 again)
  • 2z + 2z + 2 = 10
  • 4z + 2 = 10
  • 4z = 10 - 2
  • 4z = 8
  • z = 8/4
  • <u>z = 2</u>

Now, we know z (the ones digit) is 2, we can use the first equation to obtain the value of x:

  • x = z + 1
  • x = 2 + 1
  • <u>x = 3</u>

And we'll use the second equation to obtain the value of y (the tens digit):

  • y = 2x
  • y = 2(3)
  • <u>y = 6</u>

Organizing the digits, we obtain the number:

  • Number = xyz
  • <u>Number = 362</u>

As you can see, <em><u>the obtained number is 362</u></em>.

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