Answer: Children tickets cost 7.50
Adult tickets cost 12.50
Step-by-step explanation:
Let a represent adult tickets
Let c represent child tickets
On the first day she sells 6 adult tickets and 5 children tickets for total of 112.50. This can be written as:
6a + 5c = 112.50 ...... equation i
On the second day she sells 8 adult tickets and 4 children tickets for the total 130. This can be written as:
8a + 4c = 130 ....... equation ii
6a + 5c = 112.50 ...... equation i
8a + 4c = 130 ....... equation ii
Multiply equation i by 4
Multiply equation ii by 5
24a + 20c = 450 ........ equation iii
40a + 20c = 650 ......... equation iv
Subtract iii from iv
16a = 200
a = 200/16
a = 12.50
Adult tickets cost 12.50
From equation ii,
8a + 4c = 130
8(12.50) + 4c = 130
100 + 4c = 130
4c = 130 - 100
4c = 30
c = 30/4
c = 7.50
Children tickets cost 7.50
Answer:
its 104
Step-by-step explanation:
Answer:
Step-by-step explanation:
25
<h3>Answer: 395 birds</h3>
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Work Shown:
The formula to use is
A = P*(1+r)^x
where,
P = 12000 is the initial population
r = -0.15 represents the growth rate in decimal form; which is really a decay/decrease due to r being negative
x = 21 days have passed by (3 weeks = 3*7 = 21 days)
These values lead to...
A = P*(1+r)^x
A = 12000*(1+(-0.15))^21
A = 12000*(1-0.15)^21
A = 12000*(0.85)^21
A = 12000*0.03294560142183
A = 395.34721706196
A = 395
I believe it takes 1 3/5 hrs for them to finish the job together
