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Lina20 [59]
2 years ago
5

Help out Aaaaaaaañññña

Mathematics
1 answer:
frez [133]2 years ago
6 0

Answer:

The answer is 5.5

Step-by-step explanation:

+11-1/2 = +×– = += 5.5

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Which algebraic expression is a polynomial with a degree of 5?
Eddi Din [679]
The degree of a polynomial is the highest exponent or sum of exponents of the variables in the individual terms of a polynomial.

Looking at each the polynomial:

3x5 + 8x4y2 – 9x3y3 – 6y5: Degree is 6 (look at the 2nd and 3rd term)

2xy4 + 4x2y3 – 6x3y2 – 7x4: Degree is 5 (look at 1st, 2nd, and 3rd term)

8y6 + y5 – 5xy3 + 7x2y2 – x3y – 6x4: Degree is 6 (look at 1st term)

–6xy5 + 5x2y3 – x3y2 + 2x2y3 – 3xy5: Degree is 6 (look at 1st and last term)

Therefore, the answer is the second option:
2xy4 + 4x2y3 – 6x3y2 – 7x4
6 0
3 years ago
Read 2 more answers
18) The degree of P(x) = (x-1)(x+2)(x+3)(2x-5) is<br><br><br>4<br>3<br>2<br>1​
Fantom [35]

Answer:

degree 4

Step-by-step explanation:

The degree of a polynomial is determined by the term with the largest exponent for the polynomial in standard form

Given

P(x) = (x - 1)(x + 2)(x + 3)(2x - 5)

We need only consider the product of the leading terms in each factor, that is

x(x)(x)(2x) = 2x^{4} ← is the leading term in the expansion of the factors

with exponent 4

Thus polynomial is of degree 4

3 0
2 years ago
For which acute angle are the sine of the angle and cosine of the angle equal? A. 30º B. 45º C. 60º D. 75º
Vera_Pavlovna [14]
For a right triangle, the sine of an angle is the ratio of the length of the side opposite to it and the hypotenuse and the its cosine is the ratio between the side adjacent to it and the hypotenuse. From the given choices, the angle being referred to is letter B. 45°.
5 0
3 years ago
Read 2 more answers
For f(x) = 4x+ 1 and g(x) = x2 - 5, find (f+ g)(x).
horrorfan [7]

Answer:

x^2+4x-4

Step-by-step explanation:

4x+1+x^2-5

x^2+4x-4

6 0
3 years ago
Read 2 more answers
Determine the vertical asymptote for the rational function f(x) = x - 4 over 2x - 3
k0ka [10]

Answer:

x = \frac{3}{2}

Step-by-step explanation:

Given

f(x) = \frac{x-4}{2x-3}

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

Thus x = \frac{3}{2} is the vertical asymptote

5 0
3 years ago
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