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ratelena [41]
3 years ago
13

Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to the end. Ex: If oldScores = {10, 20, 3

0, 40}, then newScores = {20, 30, 40, 10}.
Computers and Technology
1 answer:
Katarina [22]3 years ago
7 0

Answer:

The code is as follows:

for(int j = 0; j < newScores.length-1; j++){  

               newScores[j] = oldScores[j+1];  

           }  

           newScores[oldScores.length-1] = oldScores[0];

Explanation:

This loop iterates through the elements of oldScores

for(int j = 0; j < newScores.length-1; j++){  

This enters the elements of oldScores to newScores starting from the element at index 1

               newScores[j] = oldScores[j+1];  

           }  

This moves the first element of index 0 to the last index of newScores

           newScores[oldScores.length-1] = oldScores[0];

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Hope this helps!
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dusya [7]
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yaroslaw [1]

Answer:

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Explanation:

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kotegsom [21]
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Read 2 more answers
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Furkat [3]

Answer:

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Explanation:

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So, the following are the reason which describe that answer is correct according to the question.

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