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ratelena [41]
3 years ago
13

Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to the end. Ex: If oldScores = {10, 20, 3

0, 40}, then newScores = {20, 30, 40, 10}.
Computers and Technology
1 answer:
Katarina [22]3 years ago
7 0

Answer:

The code is as follows:

for(int j = 0; j < newScores.length-1; j++){  

               newScores[j] = oldScores[j+1];  

           }  

           newScores[oldScores.length-1] = oldScores[0];

Explanation:

This loop iterates through the elements of oldScores

for(int j = 0; j < newScores.length-1; j++){  

This enters the elements of oldScores to newScores starting from the element at index 1

               newScores[j] = oldScores[j+1];  

           }  

This moves the first element of index 0 to the last index of newScores

           newScores[oldScores.length-1] = oldScores[0];

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In Python please.
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Answer:

negatives = []

zeros = []

positives = []

while True:

   number = input("Enter a number: ")

   if number == "":

       break

   else:

       number = int(number)

       if number < 0:

           negatives.append(number)

       elif number == 0:

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       else:

           positives.append(number)

for n in negatives:

   print(n)

for z in zeros:

   print(z)

for p in positives:

   print(p)

Explanation:

Initialize three lists to hold the numbers

Create a while loop that iterates until the user enters a blank line

Inside the loop:

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