Answer:
- Divide the resources into three parts using the corresponding process 1, process 1, and process 2 formats to maximize the use of the resources.
- Get the expected revenue by calculating the product of the total perfume in ounce and the price of an ounce of perfume.
- Increase the advertisement hours of the product.
- subtract the advert fee from the generated revenue to get the actual revenue.
- subtract the cost of production from the actual revenue to get the actual profit.
Explanation:
The get maximum profit, all the resources must be exhausted in production. The labor is divided into a ratio of 1:1:2 ( which is 5000, 5000, 1000), while the chemical units are in the ratio of 2:2:3 (10000,10000,15000). This would produce in each individual processes; 15000, 15000 and 25000 oz, which is a total of 55000 oz of perfume.
The expected revenue is $275000. If 1000oz from the 55000oz of perfume is sold without advertisement, model Jenny's awareness of the perfume increases the demand by 200oz per hour, therefore, 24hours would field 4800oz demanded, which would only take 270 hours to distribute all remaining perfumes.
The cost of production would be $130000 for labor and chemical resources plus the advert cost of $27000 ( 270 hours by 100) which is a total cost of $157000. The actual profit is $118000 ( $275000 - $157000).
Answer: True
Explanation: Because anyone can post something and it can be non reliable
Dukono is an active volcano located in the northern part of Halmahera island, Indonesia. It has a broad profile and is capped by compound craters.
Answer:
Shows the programming checking if num1 is greater than num2
Explanation:
So num1 and num2 are inputs
for you to code this you would need to put
num1=int(input("What is your first number? ))
and the same for num2 except change num1 for num 2 and first for second
When the input is completed, the computer will check if num 1 is greater than num2
it will do this by using a code something like:
if num1>num2:
Print("Your first input was greater than your second")
But in this example if it greater it just ends
But if it was less than you would put
if num1>num2:
Print("Your first input was greater than your second")
elif num1<num2:
Print("Your first input is less than your second")
So basically this code shows the computer checking if one number is greater than the other or not
