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2 years ago

Help quick please if you know

Mathematics

1 answer:

sp2606 [1]2 years ago

8 0

Answer:

what

Step-by-step explanation:

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One of the parcels weighs 2500 grams.

enot [183]

The answer is 2.5 kilograms. One kilogram is 1000 grams.

Hope this helps and hope you have a great day

4 0

3 years ago

Read 2 more answers

Is x-10 a factor of f(x)=5x^3+60x^2+109x+90

RUDIKE [14]

Answer:

Step-by-step explanation:

Given values are

f(x) = 5x^3+60x^2+109x+90

x = -10.

Given Polynomial is 5x^3+60x^2+109x+90 .

= (90)+(5.x^3)+(60.x^2)+(109.x)

By putting x = (-10) we can rewrite it as

= (90)+(5.(-10)^3)+(60.(-10)^2)+(109.(-10))

= (90)+(-5000)+(6000)+(-1090)

= 0

The remainder of given polynomial is 0.

4 0

2 years ago

Which expression is equivalent to 2(3g - 4) - (8g + 3)?

kolbaska11 [484]

Answer:

Step-by-step explanation:

6 0

2 years ago

Please tell me 11 and 12

LuckyWell [14K]

-3.66 -3 2/3 21/10 2.01

4 0

3 years ago

Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar

Brrunno [24]

The distance between the two points is $d=8.6m$

The polar coordinate of A is $\left(4.47,296.57\right)$

The polar coordinate of B is $\left(4.24,135\right)$

Explanation:

The two points are $A(2,-4)$ and $B(-3,3)$

The distance between two points is given by,

$d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6$

Thus, the distance between the two points is $d=8.6m$

The polar coordinates of A can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $A(2,-4)$ , we get,

Distance = $\sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43$

To make the angle positive, let us add 360,

$\theta=360-63.43=296.57$

The polar coordinate of A is $\left(4.47,296.57\right)$

Similarly, The polar coordinate of B can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $B(-3,3)$ , we get,

Distance = $\sqrt{(3)^{2}+(3)^{2}}=4.24$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45$

To make the angle positive, let us add 360,

$\theta=180-45=135^{\circ}$

The polar coordinate of B is $\left(4.24,135\right)$

5 0

3 years ago