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3 years ago

Is 14 times 10 to the power of 8 in scientific notation?

Mathematics

2 answers:

antoniya [11.8K]3 years ago

4 0

Answer: NO

Step-by-step explanation:

14 × 10^8 is not in scientific notation

scientific notation: a×10^b, where should be 0<a<10

As seen above, 14 is greater than 0, but also greater than 10, thus, it is not in scientific notation.

------------------

EXTRA: How to change it into proper scientific notation

To change it into scientific notation, we need to divide 14 by 10, do get 1.4. (or just move the decimal point to the left by 1 unit)

1.4 is within the range of 0-10.

1.4 × 10^9 (remember, we just divided 14 by 10, and so we need to add on the exponent by 1)

Hope this helps!! :)

Please let me know if you have any question

Andre45 [30]3 years ago

3 0

Answer: No it isn’t.

Explanation:

To make it into scientific notation:

14 x 10^8

Since 14 is above 10:

14 x 10^-1 = 1.4

But 1.4 x 10 = 14

We get: 1.4 x 10^9

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Andrei [34K]

Hello There!

The word 'became' is a linking verb.

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4 0

3 years ago

Read 2 more answers

Find the measures of the angles of the triangle whose vertices are A = (-3,0) , B = (1,3) , and C = (1,-3).A.) The measure of ∠A

alekssr [168]

Answer:

$\theta_{CAB}=128.316$

$\theta_{ABC}=25.842$

$\theta_{BCA}=25.842$

Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

We're going to use the distance formula to find the length of the sides:

$r= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

$AB= \sqrt{(-3-1)^2+(0-3)^2}=5$

$BC= \sqrt{(1-1)^2+(3-(-3))^2}=9$

$CA= \sqrt{(1-(-3))^2+(-3-0)^2}=5$

we can use the cosine law to find the angle:

it is to be noted that:

the angle CAB is opposite to the BC.

the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

$BC^2 = AB^2+CA^2-(AB)(CA)\cos{\theta_{CAB}}$

$\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}$

$\cos{\theta_{CAB}}=\dfrac{9^2-(5^2+5^2)}{-2(5)(5)}$

$\theta_{CAB}=\arccos{-\dfrac{0.62}}$

$\theta_{CAB}=128.316$

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

$\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}$

$\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)$

$\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)$

$\theta_{ABC}=\arcsin{0.4359}\right)$

$\theta_{ABC}=25.842$

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

$\theta_{BCA}=25.842$

this can also be checked using the fact the sum of all angles inside a triangle is 180

$\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180$