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artcher [175]
4 years ago
12

Who do you compare given dimensions of four triangles?

Mathematics
1 answer:
NeX [460]4 years ago
4 0

Answer:

D

Step-by-step explanation:

5+12>13

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All you need is in the photo ​
AlexFokin [52]

Answer:

X + Y = 1 ------1

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Solving by substitution method

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Putting value of y in equation 3

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X = 4 - 2

<h3>X = 2 </h3>

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Answer:

=4/3 or 1 and 1/3

If it is not provided in the answer then put no solution.

Step-by-step explanation:

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\bf \displaystyle \cfrac{d}{dx}\left[ -\int\limits_{\frac{\pi }{2}}^{u}~[cos(t^2)]dt \right]\impliedby \cfrac{df}{dx}=\cfrac{df}{du}\cdot \cfrac{du}{dx}&#10;\\\\\\&#10;\cfrac{df}{dx}=-cos(u^2)\cdot \cfrac{du}{dx}\implies \cfrac{df}{dx}=-cos(u^2)\cdot \cfrac{1}{2\sqrt{x}}&#10;\\\\\\&#10;\cfrac{df}{dx}=-cos[(\sqrt{x})^2]\cdot \cfrac{1}{2\sqrt{x}}\implies \cfrac{df}{dx}=-\cfrac{cos(x)}{2\sqrt{x}}
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