All categories

2 years ago

How you will go about preparing yourself to confidently teach numeracy?

1 answer:

8 0

In preparation of yourself in having to teach numeracy, it is best to substantiate if learning the numeracy will have benefits or advantages, such as having to help other people or even empower them as an adult people learning and think of ways how will this could be important to them.

You might be interested in

A jar contains 1,200 M&M's and everyday your family eats 1/5th of the candies. After how many days will there be 314 M&M

mrs_skeptik [129]

The equation is 314 = 1,200 - 240x

1,200 is the number of M&M's it starts with
The problem said the family eats 1/5th of the candy every day
1/5 of 1,200 is 240
It is a -240 because the amount of m&m's is getting fewer each day
The x stands for the number of days

Sorry but I'm not sure if I could answer your problem exactly
The answer is 3.69 days
Because there isn't an exact day that there would exactly 314 M&M's left

7 0

2 years ago

Solve for x 12 (x + 2)/ B O 14 O 10 12 06

Makovka662 [10]

Answer:

opposite sides of ||gram are equal and parallel therefore

12=x+2

12-2=x

10=x

pls mark as brainliest

6 0

2 years ago

Felicia used 153 Yellow beads and some green beads for her art project. She used 9 times as many Yellow beads as green beads. Ho

Vlada [557]

Answer:

Step-by-step explanation:

To find the number of green beads that Felicia used, we first need to list out what we know.

Let x = number of green beads.

Yellow Beads = 153

So we get:

x*9 = 153

We divide both sides by nine to find the value of x.

$\dfrac{x*9}{9}=\dfrac{153}{9}$

x = 17

To see if we got the answer correct, let's substitute x.

x * 9 = 153

17 * 9 = 153

153 = 153

7 0

3 years ago

How do i solve this (15 points)

GaryK [48]

Multiply 64 and 12 three times and 64 ×12=? then ?×3=?

3 0

3 years ago

find the volume of the solid formed by revolving the region bounded by the graphs of y = 4x - x^2 and f(x) = x^2 from [0,2] abou

Neko [114]

Answer:

$v = \frac{32\pi}{3}$

$v=33.52$

Step-by-step explanation:

Given

$f(x) = 4x - x^2$

$g(x) = x^2$

$[a,b] = [0,2]$

Required

The volume of the solid formed

Rotating about the x-axis.

Using the washer method to calculate the volume, we have:

$\int dv = \int\limit^b_a \pi(f(x)^2 - g(x)^2) dx$

Integrate

$v = \int\limit^b_a \pi(f(x)^2 - g(x)^2)\ dx$

$v = \pi \int\limit^b_a (f(x)^2 - g(x)^2)\ dx$

Substitute values for a, b, f(x) and g(x)

$v = \pi \int\limit^2_0 ((4x - x^2)^2 - (x^2)^2)\ dx$

Evaluate the exponents

$v = \pi \int\limit^2_0 (16x^2 - 4x^3 - 4x^3 + x^4 - x^4)\ dx$

Simplify like terms

$v = \pi \int\limit^2_0 (16x^2 - 8x^3 )\ dx$

Factor out 8

$v = 8\pi \int\limit^2_0 (2x^2 - x^3 )\ dx$

Integrate

$v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0$

$v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0$

Substitute 2 and 0 for x, respectively

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])$

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ 0 - 0])$

$v = 8\pi [ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ]$

$v = 8\pi [ \frac{16}{3} - \frac{16}{4} ]$

Take LCM

$v = 8\pi [ \frac{16*4- 16 * 3}{12}]$

$v = 8\pi [ \frac{64- 48}{12}]$

$v = 8\pi * \frac{16}{12}$

Simplify

$v = 8\pi * \frac{4}{3}$

$v = \frac{32\pi}{3}$

$v=\frac{32}{3} * \frac{22}{7}$

$v=\frac{32*22}{3*7}$

$v=\frac{704}{21}$

$v=33.52$

8 0

2 years ago