Question:
At noon a tank contains 6 cm of water after several hours it contains 3 cm of water what is the percent decrease of water in the tank
Answer:
The percent Decrease of water in the tank is 50%
Step-by-step explanation:
Given:
Initial amount of water in the tank at the noon = 6 cm
amount of water remained in water after several hours = 3 cm
To Find:
The percent decrease =?
Solution:
The percent decrease in the tank
=>
Substituting the values
=>
=>
=>
=> 50
Answer:
every 10th student entering the school
Step-by-step explanation:
Answer:
Send q picture of the graphs so I can help
Step-by-step explanation:
need pictures of graph
For the answer to the question above,
2x + 4y = –7 (1)
y = -1/2x + 5 (2)
Putting (2) into (1), we have:
-2x + 4(-1/2x + 5) = -7
-2x - 2x + 5 = -7
-4x = -7 - 5 = -12
x = -12/-4 = 3
y = -1/2(3) + 5 = -3/2 + 5 = 7/2
Therefore there is only one solution
I hoipe my answer helped you. Feel free to ask more questions. Have a nice day!
Answer:
- x² - 8x + 12
- x³ + 2x² - 15x - 36
- x³ -2x² - 15x
Step-by-step explanation:
#1) Find the polynomial with roots at 2 and 6
-
(x -2)(x - 6) = x² - 8x + 12
#2) Find the polynomial with a double root at -3 and another root at 4
-
(x+3)(x+3)(x-4) = (x²+6x+9)(x-4) = x³ + 2x² - 15x - 36
#3) Find the polynomial with roots 0, -3 and 5
- (x -0)(x+3)(x-5) = x(x²-2x - 15) = x³ -2x² - 15x