Help please! Fully factorise

Mathematics

2 answers:

poizon [28]3 years ago

4 0

Answer:

a.8y³-6y

taking common

2y(4y²-3)

is a required answer

3x²-20x+12

doing middle term factorization

3x²-18x-2x+12

3x(x-6)-2(x-6)

(x-6)(3x-2)

is a required answer .

Anvisha [2.4K]3 years ago

3 0

A. 2y(4y^2-3)

B (x-6) -2 (x-6)

You might be interested in

Evaluate $\dfrac{2\sqrt{72}}{\sqrt{8}+\sqrt{2}}$.

Pavlova-9 [17]

<h3>Answer: 4</h3>

========================================================

Work Shown:

$\frac{2\sqrt{72}}{\sqrt{8}+\sqrt{2}}\\\\\frac{2\sqrt{36*2}}{\sqrt{4*2}+\sqrt{2}}\\\\\frac{2\sqrt{36}*\sqrt{2}}{\sqrt{4}*\sqrt{2}+\sqrt{2}}\\\\\frac{2*6*\sqrt{2}}{2*\sqrt{2}+\sqrt{2}}\\\\\frac{12\sqrt{2}}{2\sqrt{2}+\sqrt{2}}\\\\\frac{12\sqrt{2}}{3\sqrt{2}}\\\\\frac{12}{3}\\\\4$

Note in step 2, I factored each number in the square root to pull out the largest perfect square factor. From there, I used the rule that $\sqrt{A*B} = \sqrt{A}*\sqrt{B}$ to break up the roots.