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Bad White [126]
3 years ago
11

Help please! Fully factorise

Mathematics
2 answers:
poizon [28]3 years ago
4 0

Answer:

a.8y³-6y

taking common

<u>2y(4y²-3)</u>

is a required answer

b.

3x²-20x+12

doing middle term factorization

3x²-18x-2x+12

3x(x-6)-2(x-6)

<u>(x-6)(3x-2)</u>

<u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u> </u><u>.</u>

Anvisha [2.4K]3 years ago
3 0
A. 2y(4y^2-3)

B (x-6) -2 (x-6)
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What is the value of 0.8–0.6? Write your answer as a fraction in lowest terms
Nesterboy [21]

Given expression:

  • 0.8 - 0.6

To simplify the expression as a fraction in simplest form, let us multiply both terms by 10. Then, both terms must also be divided by 10.

   \implies \dfrac{[10(0.8) - 10(0.6)]}{10}

   \implies \dfrac{[8 - 6]}{10}

   \implies \dfrac{[2]}{10} = \dfrac{2}{10}

When 2/10 is simplified in lowest terms, we get;

   \implies \dfrac{2}{10} \implies \dfrac{1 \times 2}{5 \times 2} \implies \dfrac{1}{5}

Therefore, 0.8 - 0.6 in fraction form is 1/5.

4 0
2 years ago
Select all the expressions that equal -2 + 5. A -2 - (-5) B -2 - 5 C 5 - 2 D 5 + (-2)
Helga [31]

Answer:

A

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
What do the fractions 10/16; 15/24; 20/32; 25/40; and 30/48 have in common?
Alex17521 [72]

Answer:

The Highest Common Factor is 8

Step-by-step explanation:

This is called ' Highest Common Factor'

Considering the denominators which are 16, 24, 32, 40 and 48

16 = 2×2×2×2

24 = 2×2×2×3

32 = 2×2×2×2×2

40 = 2×2×2×5

48 = 2×2×2×2×3

What they have in common most is 2×2×2 = 8

5 0
3 years ago
Can someone please help me with this assignment
KIM [24]
These are 8 questions and 8 answers.

Page 1:

1) Triangle ABC has vertices A(-2,1), B(0,5), and C (8,1). What type of triangle is triangle ABC


Answer: option A. acute triangle.

Explanation:

Determine the lengths of the three sides:

Side AB: √[(0+2)^2 + (5-1)^2 ] = √ [4 + 16] = √(20)

Side BC: √ [ (8-0)^2 + (1 -5)^2 ] = √ [ 64 + 16 ] = √(86)

Side AC: √ [ (8 + 2)^2 + (1 - 1)^2 ] = √100 = 10

Compare the square of the side length of the largest side with the sum of the squares of the other two sides.:

AC^2 = 100
BC^2 = 86
AB^2 = 20

BC^2 + AB^2 = 86 + 20 = 106

100 < 106 => AC^2 < BC^2 + AB^2 =>

all the angles are less than 90°, which means the triangle is actue.

That is becasue when the square of the largest side is equal to the sum of the squares of the smaller sides, there is a right angle and the triangle is a right triangle (Pytaghorean theorem). When the square of the largest side is less than the sum of the squares of the other two sides, the angle is less than 90°, and the triangle is acute.

2) Which set represents the side lengths of a right trianle?

Answer: option C: 9, 12, 15

Explanation:

Check whic set obeys Pythagorean theorem.

15^2 = 225
12^2 = 144
9^2 = 81
.
144 + 81 = 225 => 15^2 = 12^2 + 9^2 => right triangle

3) Which property disproves the statement in the student's notes?

Answer: option B) all angles of a rhombus are not congruent.

Explanation:

A rhombus is a quadrilateral whose four sides all have the same length. It is a quadrilateral.

The angles do not need to be congruent. Only the square, which is only one special case of rhombus, has the four angles congruent, but the masure of the angles of other rhombus are not equal.

4) What is the are of the figure?

Answer: 85 unit^2

Explanation:

1) Area of the rectangle = base * height  = 4 * 9 = 36
2) area of the trapezoid = height * half of the sum of the bases = 7 * (3+7)/2 = 35
3) area of the rhombus = half the product of the diagonals = 7 * 4 / 2 = 14

Result: 36 + 35 + 14 = 85

That option is not among the choices. The nearest one is 84 unit^2.

Page 2 is the same page 1.

Page 3:

5) Question 8:

What line can be used to draw the altitude of the triangle FGH

Answer: option D: 3y = 7x + 16

Explanation:

1) All triangles have 3 altitudes (one for each vertex).

2) Now I am going to find the altitude of the vertex H (respect to base FG.

3) First calculate the slope of the segment FG:

slope = [y2 - y1] / [x2 - x1]

x2, y2 are the coordinates of the point G (6, -2) and x1, y1 are the coordinates of the point F (-8,4)

=> slope = [ -2 - 4] / [6 - (-8) ] = [-6] / [14] = - 3/7

4) Now calculate the slope of the perpendicular line (because the altitude is perpendicular to the base).

The lines of perpendicular lines obey the rule: slope line A = - slope line B / 2

So, the slope of the line perpendicular to the base is - [1 / (-3/7) ] = 7/3

5) The equation of the line with slope 3/7 that contains the point H (-4, - 4) is:

y - (-4)        7
--------- =  -----
x - (-4)       3

=> 3(y + 4) = 7(x + 4)

=> 3y + 12 = 7x + 28

=> 3y = 7x + 28 - 12

=> 3y = 7x + 16 which is the answer

6) Question 8. How will be the volume affected

Answer: option c. the volume will be 9 times larger.

Explanation:

1) Formula of the volume of rectagular prism

Volume = length * width * height

2) Name, V the volume, l the length, w the width, h the heigth => V = l * w * h

3) Triple the length and the width:

New volume = 3l * 3w * h = 9 l * w * h = 9V

4) You have proved that the new volumen is 9 times the original volume, which is the option c.


7) Question 9

What is the approximate length of the median of the trapezoid ABCD.

Answer: option b. 7.8 units

Explanation:

1) The median of a trapezoid is half the sum of the two parallel segments

2) The two parallel segments are AB and CD

3) The length of the segment AB is:

AB^2 = (3+7)^2 + (7-2)^2 = 10^2 + 5^2 = 100 + 25 = 125

=> AB = √125 ≈ 11.18

4) The length of the sement CD is:

CD^2 = (3 + 1)^2 + (1+1)^2 = 4^2 + 2^2 = 16 + 4 = 20

=> CD = √20 ≈ 4.47

5) The median is [11.48 + 4.47] / 2 ≈ 7.83 => option b.

8) Question 10. Problem

Answer: option B. 34.8 feet

Explanation:

1) Variables:

Ha = 4 ft (heigth of Abigail)
α = 38°
s = 50 ft (length of the string)
Hk = ? (altitude of the kite)

2) formula of sine ratio:

sin α = opposite-leg / adjacent leg

3) solution

sin α = x / s => x = sinα * s = sin(38°) * 50 ft = 30.78 ft

Hk = x + Ha = 30.78 ft + 4 ft = 34.78 ft => aption B. 34.8 feet
8 0
3 years ago
If x is an even integer greater than 3, then, in terms of
prisoha [69]

Answer:

x^2

Step-by-step explanation:

Any even number raised to two is even.

Eg: 4^2 = 16

12^2 = 144

Etc...

And

Any odd number raised to two is odd.

Eg: 5^2 = 25

13^2 = 169

Etc...

And also x^2 is greater than 2x & x+3 & x+2

6 0
2 years ago
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