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ANTONII [103]
3 years ago
7

A data set is made up of these values.

Mathematics
1 answer:
Elis [28]3 years ago
7 0

Answer:

The answer is b

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Select the correct answer.
dlinn [17]

Answer:

E. 25%

Step-by-step explanation:

3/12=0.25

black dots divided by total dots

3 0
2 years ago
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How do you do this? can someone explain it to me please?​
My name is Ann [436]

Answer:

you have to detect the angles on itmeasure the angles on the empty side wheree there are no numbers based on what the other side is

Step-by-step explanation:

7 0
3 years ago
Find the slope of the line,<br> HELPPPP
nlexa [21]

Answer:

Slope: 2

Step-by-step explanation:

The slope of a line is when x increases by an amount, y increases by an amount. We can find the slope of a linear graph by taking 2 points. I will use (0,3) and (-1,1)

We see that the y-values are 4 from each other, and that the x-values are 2 from each other.

Now, we can use a method called rise over run, which is y-value/x-value.

\frac{4}{2} =2

Therefore, the slope is 2.

7 0
2 years ago
Josh ran 84.6 miles in June. In July he ran 0.55 times this distance due to an injury. How many more miles did he run in June th
Irina-Kira [14]

I did 0.80-0.25=0.55

so I figured that is what she had left so I know took the total 0.80-0.55 and got0.25 which is B.

My friend said the correct answer was A.

Don't worry I just did this problem!

5 0
2 years ago
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how can you determine that the polynomial function does not have any zeros with even Multiplicity? Explain.​
quester [9]

Answer:

See Below.

Step-by-step explanation:

Remember multiplicity rules:

  • If a factor has an odd multiplicity (e.g. 1, 3, 5...), then the graph will cross the x-axis at that point.
  • If a factor has an even multiplicity (e.g. 2, 4, 6...), then the graph will bounce off the x-axis at that point.

From the graph, we can see that at our zeros, the graph always passes through the x-axis.

Hence, we do not have any zeros with even multiplicity since the graph does not "bounce" at any of the zeros.

3 0
3 years ago
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