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2 years ago

11

Beth added 1 1/4 pounds of fruit to a fruit basket Her son took 2 3/8 pounds of fruit out of the basket What was the total chang

e in pounds of fruit in the fruit basket?

1 answer:

WARRIOR [948]2 years ago

7 0

In total 1.125 pounds were removed from the basket

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I really need this answer please help

iren2701 [21]

I’m not completely sure but I think the answer is C.

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2 years ago

(-1/3) to the power of five?

Bumek [7]

$\bf \left( -\cfrac{1}{3} \right)^5\implies \left( -\cfrac{1}{3} \right)\left( -\cfrac{1}{3} \right)\left( -\cfrac{1}{3} \right)\left( -\cfrac{1}{3} \right)\left( -\cfrac{1}{3} \right)\implies -\cfrac{1^5}{3^5}\implies -\cfrac{1}{243}$

recall minus * minus * minus * minus * minus is minus.

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3 years ago

What is 64% of 680kg

Anuta_ua [19.1K]

Answer:

435.2kg (1DP)

Step-by-step explanation:

0.64x680

64 divided by 100 = 0.64

4 0

2 years ago

Read 2 more answers

Given the following functions, find and simplify (f • g)(x) f(x)=—x+3 g(x)=-x-1

Hitman42 [59]

Answer:

$(f\circ g)(x)= x + 4$

Step-by-step explanation:

<u>Composite Function</u>

Given f(x) and g(x) as real functions, the composite function $(f\circ g)(x)$ is defined as:

$(f\circ g)(x)=f(g(x))$

It can be found by substituting g into f.

We are given the functions:

f(x) = -x + 3

g(x) = -x -1

Find

$(f\circ g)(x)=f(g(x))= - (-x -1) + 3$

Removing parentheses:

$(f\circ g)(x)= x + 1 + 3$

Simplifying:

$\mathbf{(f\circ g)(x)= x + 4}$

5 0

2 years ago

How would I do this question.

olga2289 [7]

Answer:

The density of cube is 6.17959 $\frac{g}{cm^{3} }$

Step-by-step explanation:

The density is given by ration of a mass of body and volume occupied by a body.

$\rho = \frac{m}{V}$

Where,

$\rho$ is density.

m is mass of a body

V is the volume of a body

Given that one side of the cube is 0.53cm

Hence, the volume of a body is V= $0.53^{3}$ =0.148877 $cm^{3}$

Now, the Density of the cube will be

$\rho = \frac{m}{V}$

$\rho = \frac{0.92}{0.148877}$

$\rho =6.17959$

Thus, The density of cube is 6.17959 $\frac{g}{cm^{3} }$

3 0

3 years ago