Can someone help me pls pls help with this question

An automobile manufacturer has given its car a 46.7 miles/gallon (MPG) rating. An independent testing firm has been contracted t

erastova [34]

Answer:

$z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23$

The p value would be given by:

$p_v =2*P(z$

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

Step-by-step explanation:

Information given

$\bar X=46.5$ represent the mean

$\sigma=1.1$ represent the population standard deviation

$n=150$ sample size

$\mu_o =46.7$ represent the value to verify

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean for this case is 46.7, the system of hypothesis would be:

Null hypothesis: $\mu = 46.7$

Alternative hypothesis: $\mu \neq 46.7$

Since we know the population deviation the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Replacing we got:

$z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23$

The p value would be given by:

$p_v =2*P(z$

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

7 0

2 years ago

Liliana wants to determine the height of an enlarged photo that she plans to frame. The original photo was 11 inches wide by 14

vova2212 [387]

For this case, the first thing we must do is find the scale factor.

For this, we use one of the dimensions. We will use the width of the photo.

We have then:

$k = \frac {132} {11}\\k = 12$