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Liula [17]
2 years ago
13

PLEASE !!! HELP D: lord pls

Mathematics
2 answers:
Sonja [21]2 years ago
8 0
It might be 4 I think
pickupchik [31]2 years ago
6 0

Answer:

the answer is 4 have a nice day

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EVALUATE THE FOLLOWING:<br> A) 85!/82!<br> B) nC0<br> C) nPn
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Answer:

Step-by-step explanation:

85!/82! = 85*84*83 = 592620

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Anna11 [10]

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Answer:

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3 years ago
How many 7-digit phone numbers are possible, assuming that the first digit can’t be a 0 or a 1? (b) re-solve (a), except now ass
sladkih [1.3K]
A. We are going to form 7 digit numbers from the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

where the first digit cannot be 0 or 1.

so we have 8 choices for the 1. digit, and 10 choices for all the other 6 digits.

this means there are 8*10*10*10*10*10*10=8* 10^{6} possible numbers.

b.

consider the numbers which start with 911. There are 10*10*10*10=10 ^{4} such numbers, since for the 4th, 5th, 6th and 7th digits we have 10 choices.

then we remove this number, from the one we found in a:

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Answer:

a.8*10^{6}
b.7,990,000

3 0
3 years ago
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