The average distance from Earth to the Moon is approximately 238,900 miles. what is the distance in scientific notations?

so There are 17 girls and 119 boys on a class field trip to the museum. The students need to be broken up into the largest possi

Step2247 [10]

1 student in each group with 126 groups in total

8 0

2 years ago

Figure ABCD is reflected across the x-axis. What are the coordinates of A' , B' , C' , and D' ? Enter your answer in each box.

stealth61 [152]

Answer:

The coordinates of ABCD after the reflection across the x-axis would become:

A'(2, -3)

B'(5, -5)

C'(7, -3)

D'(5, -2)

Step-by-step explanation:

The rule of reflection implies that when we reflect a point, let say P(x, y), is reflected across the x-axis:

x-coordinate of the point does not change, but

y-coordinate of the point changes its sign

In other words:

The point P(x, y) after reflection across x-axis would be P'(x, -y)

P(x, y) → P'(x, -y)

Given the diagram, the points of the figure ABCD after the reflection across the x-axis would be as follows:

P(x, y) → P'(x, -y)

A(2, 3) → A'(2, -3)

B(5, 5) → B'(5, -5)

C(7, 3) → C'(7, -3)

D(5, 2) → D'(5, -2)

Therefore, the coordinates of ABCD after the reflection across the x-axis would become:

A'(2, -3)

B'(5, -5)

C'(7, -3)

D'(5, -2)

8 0

2 years ago

The data below are the ages and systolic blood pressures (measured in millimeters of mercury) of 9 randomly selected adults. Wha

seraphim [82]

Answer:

$\sum_{i=1}^n x_i =459$

$\sum_{i=1}^n y_i =1227$

$\sum_{i=1}^n x^2_i =24059$

$\sum_{i=1}^n y^2_i =168843$

$\sum_{i=1}^n x_i y_i =63544$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=24059-\frac{459^2}{9}=650$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}=63544-\frac{459*1227}{9}=967$

And the slope would be:

$m=\frac{967}{650}=1.488$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{459}{9}=51$

$\bar y= \frac{\sum y_i}{n}=\frac{1227}{9}=136.33$

And we can find the intercept using this:

$b=\bar y -m \bar x=136.33-(1.488*51)=60.442$

So the line would be given by:

$y=1.488 x +60.442$

And then the best predicted value of y for x = 41 is:

$y=1.488*41 +60.442 =121.45$

Step-by-step explanation:

For this case we assume the following dataset given:

x: 38,41,45,48,51,53,57,61,65

y: 116,120,123,131,142,145,148,150,152

For this case we need to calculate the slope with the following formula:

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

So we can find the sums like this:

$\sum_{i=1}^n x_i =459$

$\sum_{i=1}^n y_i =1227$

$\sum_{i=1}^n x^2_i =24059$

$\sum_{i=1}^n y^2_i =168843$

$\sum_{i=1}^n x_i y_i =63544$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=24059-\frac{459^2}{9}=650$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}=63544-\frac{459*1227}{9}=967$

And the slope would be:

$m=\frac{967}{650}=1.488$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{459}{9}=51$

$\bar y= \frac{\sum y_i}{n}=\frac{1227}{9}=136.33$

And we can find the intercept using this:

$b=\bar y -m \bar x=136.33-(1.488*51)=60.442$

So the line would be given by:

$y=1.488 x +60.442$

And then the best predicted value of y for x = 41 is:

$y=1.488*41 +60.442 =121.45$

3 0

3 years ago

I need help with this math today

Genrish500 [490]

Answer:

120 + 10x

or

10(12 + x)

Step-by-step explanation:

5 0

2 years ago

I need help with part b and c pretty p please show your work so I can do this

stiks02 [169]

It is black just letting u know

6 0

3 years ago

The average distance from Earth to the Moon is approximately 238,900 miles. what is the distance in scientific notations?​

The average distance from Earth to the Moon is approximately 238,900 miles. what is the distance in scientific notations?