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3 years ago

The Cubs have won

Mathematics

1 answer:

Naily [24]3 years ago

4 0

First you need to figure out the games the Cubs lost. 11-7=4, so they lost 4 games.

Now you must plug in the ratio of games lost to games played. You know they lost 4 games and played 11, so the ratio would be 4:11.

I hope you find this helpful :)

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What is the answer to 7(1 + 4k)

Sophie [7]

How to solve it:
•1. multiply 7 x 1= 7
•2. multiply 7 x 4k= 28k

so the answer is: 7+28k

i hope i have been helpful :)

8 0

2 years ago

Read 2 more answers

I need help with these 2 questions.

Usimov [2.4K]

The first one is 32m^15n^10
The second one is:
(h^12/h^4)^5
(h^6/h)^5
h^30/h^5
h^25/h

Hope this helps :)

3 0

2 years ago

Please help me!!!!!!!!!!!

shutvik [7]

The given parabola is $y+4=12(x-7)^2$ . Compare with the standard equation of a parabola in vertex form, $y-c=a(x-b)^2$ .

The vertex of this parabola is $(b,c)$ . Compare $y+4=12(x-7)^2$ with the standard equation $y-c=a(x-b)^2$ .

we see $c=-4,b=7$ . Thus, the vertex of the given parabola is $(7,-4)$ .

8 0

3 years ago

Read 2 more answers

Ype the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.

rewona [7]

Answer:

4/8 or 1/2

Step-by-step explanation:

Convert all size to x/8

1/4=2/8 and 1/2=4/8

Multiply size of beaker by how many there are filled

1/8 * 2= 2/8

2/8*7= 14/8

4/8*3 =12/8

then add all of them together = 28/8

convert 4 liters to 32/8

Subtract 32/8 - 28/8 = 4/8

4 0

2 years ago

Marcellus has a pitcher that contained 5/8 gallon limeade. Marcellus drank 1/4 gallon of the limeade, and Marcy drank 1/8 gallon

mash [69]

Answer:

2/5

Step-by-step explanation:

Given Marcellus drank 1/4 gallon of the limeade and Marcy drank 1/8 gallon of the limeade

Given that only 5/8 portion of the pitcher contains limeade

Total amount drunk = amount drunk by Marcellus + amount drunk by Marcy

Total amount drunk = $\frac{1}{4} +\frac{1}{8}$ = $\frac{3}{8}$

The amount of Limeade remained = The amount initially - the amount drunk

The amount remained = $\frac{5}{8} -\frac{3}{8}$ = $\frac{1}{4}$

Fractional part = amount remained / amount initially = $\frac{\frac{1}{4} }{\frac{5}{8} }$ = $\frac{2}{5}$

8 0

2 years ago