Hey There!
8x^46=8x(40+
We move all terms to the left:
8x^46-(8x(40+)=0
complette the square to get vertex form or y=a(x-h)^2+k
(h,k) is vertex
1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
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2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
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3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
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4. complete the squre and expand
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so
y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)
Answer:
Step-by-step explanation:
123/6 x 7[(654 + 2) x (12/3)].....do whats in parenthesis first
123/6 x 7[656 x 4] ......do whats in brackets
123/6 x 7(2624) ....do multiplication/division from left to right, whichever comes first
20.5 x 18,368 =
376544 <===
Answer:
9
Step-by-step explanation:
9/9=1
27/9=3
