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2 years ago

15

The number of adults going on a field trip was the largest prime number less than 50. How many adults were going on the field tr

ip?

1 answer:

Vilka [71]2 years ago

4 0

Answer:

47

Step-by-step explanation:

Well 47 is the highest prime number that is smaller than 50

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Y is directly proportional to x and inversely proportional to the square of w. Give the equation:

Goshia [24]

Answer: y=kx/w^2

Step-by-step explanation:

y is directly proportional to x

y∝x

y=kx

y inversely proportional to the square of w.

y ∝ (1/(w)^2)

y=k/w^2

y=kx/w^2

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1 year ago

A circle has a radius of 2.6 centimeters.What is the circumference,in centimeters,of the circle?

Tju [1.3M]

37.699cm

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3 years ago

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13. Find the length of the diagonal of the rectangular prism.

vova2212 [387]

Answer:

:0 no one knows

Step-by-step explanation:

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2 years ago

LCM of two numbers is 1134 and HCF is 18. if one of the numbers is 162, find the other. number.<br>

Brilliant_brown [7]

<h3>Answer: 126</h3>

=====================================================

Work Shown:

Let x and y be the two numbers.

We're given x = 162 and the variable y is unknown.

We're also given LCM = 1134 and HCF = 18

So,

LCM = (x*y)/HCF

1134 = 162*y/18

1134 = (162/18)y

1134 = 9y

9y = 1134

y = 1134/9

y = 126

The other number is 126

---------------------

Notice that

162 = 18*9
126 = 18*7

showing that 18 is the highest common factor (HCF) of the numbers 162 and 126. This partially confirms the answer.

Now let,

A = multiples of 162
B = multiples of 126

So,

A = 162, 324, 486, 648, 810, 972, 1134, 1296, ...
B = 126, 252, 378, 504, 630, 756, 882, 1008, 1134, 1260, ...

We see that 1134 is in each list of multiples and the smallest such common item. So the lowest common multiple (LCM) of 162 and 126 is 1134. This helps fully confirm the answer.

7 0

1 year ago

Find the area of the trapezoid. points are (-5,-3)(4,-3)(6,-7)(-7,-7)

Olegator [25]

Answer:

44 square units

Step-by-step explanation:

The area of a trapezoid with bases b₁ and b₂ and height h is given by the formula

$A=\left(\dfrac{b_1+b_2}{2}\right)h$

If you're wondering how we get this formula, check the attached illustration (remember the area of a parallelogram is its base multiplied by its height)! Moving on to our trapezoid, the pairs of points (-5,-3)(4,-3) and (6,-7)(-7,-7) form two horizontal segments, which form b₁ and b₂, and our height is the distance between the y-coordinates -3 and -7, which is 4. We can find b₁ and b₂ by finding the distance between the x coordinates in their pairs of points:

$b_1=|-5-4|=|-9|=9\\b_2=|6-(-7)|=|6+7|=13$

Putting it altogether:

$A=\left(\dfrac{9+13}{2}\right)(4)=\left(\dfrac{22}{2}\right)(4)=(11)(4)=44$

So the area of our trapezoid is 44.

4 0

2 years ago