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Snezhnost [94]
3 years ago
10

What kind of angle is created by the intersection of two perpendicular lines, rays, or line segments

Mathematics
2 answers:
Law Incorporation [45]3 years ago
8 0

it is a right angle! the angle formed by perpendicular lines is a 90 degree angle.

lina2011 [118]3 years ago
4 0

Answer: Right angle

Step-by-step explanation:

APex

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1/(x-2)+1/(x+3)=1/5 solve the problem for me​
Gennadij [26K]

════════ ∘◦❁◦∘ ════════

<h3>Final value : x² -9x - 11</h3>

════════════════════

<h3>Step by step </h3>

\frac{1}{(x - 2)}  +  \frac{1}{(x + 3)}  =   \frac{1}{5}

\frac{(x + 3) + (x - 2)}{(x - 2)(x + 3)}  =  \frac{1}{5}

\frac{2x + 1}{ {x}^{2} + 3x - 2x - 6 }  =  \frac{1}{5}

\frac{2x + 1}{ {x}^{2}  + x - 6}  =  \frac{1}{5}

2x + 1 = ⅕ × (x² + x - 6)

2x + 1 = ⅕x² + ⅕x - 6/5

1/5x² +1/5x - 2x - 6/5 - 1 = 0

1/5x² -9/5x - 11/5 = 0

x² - 9x - 11 = 0. #times by 5

════════════════════

#Give me brainliest pls im tired typing all of this

8 0
3 years ago
Find the inverse of 2∛(x+2)
Artemon [7]
y=2\sqrt[3]{x+2}\ \ \ |divide\ both\ sides\ by\ 2\\\\\sqrt[3]{x+2}=\dfrac{y}{2}\to x+2=\left(\frac{y}{2}\right)^3\ \ \ |subtract\ 2\ from\ both\ sides\\\\x=\dfrac{y^3}{2^3}-2\\\\x=\dfrac{1}{8}y^3-2\\\\\boxed{f(x)=2\sqrt[3]{x+2}\to f^{-1}(x)=\frac{1}{8}y^3-2}
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What is the missing number?<br><br> Question 4 options:
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Answer:

i dont see it

Step-by-step explanation:

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Solve for x:<br> -14x &gt; -3
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Answer:

x>11

Step-by-step explanation:

-14x>-3

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x > 11

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3 years ago
* WORTH 30 Points *
yawa3891 [41]
Any multiple of (-2x+3y=18) would constitute an "other equation" forming a system with an infiinite number of solutions.  The reason for that is that the two equations would be "dependent."

On the other hand, looking at the system

<span>-2x+ 3y= 18
</span><span>-2x+ 3y= 19

we see that there is no solution.  Why?  Because -2x + 3y cannot equal 18 and 19 at the same time.  You'd have two non-intersecting, parallel lines.

</span>
7 0
3 years ago
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