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ANEK [815]
3 years ago
12

Find the value of X.

Mathematics
1 answer:
nataly862011 [7]3 years ago
7 0
RS + ST = RT

3x + 1 + 2x - 2 = 64
5x - 1 = 64
5x = 64 + 1
5x = 65
x = 65/5
x = 13 <==

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How many 9's are in 99
MrRissso [65]

Answer:

11 or 2

Step-by-step explanation:

11: You take 99/9 to see how many times 9 could go into 99, which would be 11.

2: You just look at the number and you see that there are 2 9s in 99.

-I hope this helps!-

-I didn't know which answer you were looking for so I put both!-

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4 0
3 years ago
5x+2=5x+2 has how many solutions?
tigry1 [53]
It has 1 solution i believe
8 0
3 years ago
The ones that are blank...
alex41 [277]
You put number nine in the form of y=kx
6 0
3 years ago
HURRY PLSS
Ipatiy [6.2K]
I think C is the answer.

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So, your answer:
C



4 0
4 years ago
Read 2 more answers
sasha has some pennies nickels and dimes in her pocket. the number of coins is 18 the expression is 0.01p+0.05n+0.10d represents
Lapatulllka [165]

Answer:

3 pennies, 9 nickels, and 6 dimes

Step-by-step explanation:

We have three conditions:

(1)         p +        n +        d = 18

(2) 0.01p + 0.05n + 0.10d = 1.08

(3)                                   d = 2p

Multiply (2) by 100 and rearrange (3) to get a standard array.

(4)      p +   n +     d =   18

(5)      p + 5n + 10d = 108

(6)  -2p          +     d =    0

Subtract (4) from (5). This gives

(4)      p +   n +   d =  18

(7)            4n + 9d = 90

(6)  -2p          +   d =   0

Multiply (4) by 2 and add to (6). This gives

(4) p +   n +    d =  18

(7)        4n + 9d = 90

(8)        2n + 3d = 36

Double (8) and subtract from (7). This gives

(4)      p +   n +   d = 18

(7)            4n + 9d = 90

(9)                    3d = 18

Divide (9) by 3. This gives

(10) d = 6

Substitute (10) into (7). This gives

4n + 9(6) = 90

4n +   54 = 90

4n           = 36

(11) n       =    9

Substitute (10) and (11) into (4). This gives

p + 9 + 6 = 18

p +      15 = 18

p              =  3

Sasha has 3 pennies, 9 nickels, and 6 dimes.

6 0
4 years ago
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