Every time you add one to the first number you add 3 to the second number. The next set of numbers would then be (4,10).
Hope this helps :)
Answer:
37. {-1, -1}.
Step-by-step explanation:
I'll solve the first one . The other can be solved in a similar way. We can use the method of elimination.
x1 - x2 = 0
3x1 - 2x2 = -1
We can multiply the first equation by -2. We then have an equation containing + 2x2 so when we add this to the second equation the 2x2 will be eliminated
So the first equation becomes:
-2x1 + 2x2 = 0 Bring down the second equation:
3x1 - 2x2 = -1 Now adding, we get:
x1 + 0 = -1
so x1 = -1.
Now we substitute this value of x1 in the original first equation:
-1 - x2 = 0
-1 = x2
x2 = -1.
So the solution set is {-1, -1}.
If there are more than 2 equations you can use a combination of substitutions and eliminations.
This question involves basic arithmetic signs and simplifying of bracket terms.
Mobile number is; 9 6 4 1 2 7 8 1 2 3
a) 2x - 5 = 7
Add 5 to both sides to get;
2x = 12
x = 12/2
x = 6
b) 2(p + 1) = p + 4
Expanding the bracket gives;
2p + 2 = p + 4
Rearranging gives;
2p - p = 4 - 2
p = 2
c) 5(y + 1) = 25
Expanding the bracket gives;
5y + 5 = 25
5y = 25 - 5
5y = 20
y = 20/5
y = 4
d) 5(q –1) + 3q = 10 + 1
Expanding the bracket gives;
5q - 5 + 3q = 11
2q - 5 = 11
add 5 to both sides to get;
2q = 16
q = 16/2
q = 8
Question E and F are not clear but as it is r and z that are yet to be gotten, i have gotten the right equations from the brainly link at the end of this page.
e) 8z - 8 = 6z + 8
Rearranging, we have;
8z - 6z = 8 - 6
2z = 2
z = 2/2
z = 1
f) 3(r+10) + 200 = 236
Expanding the bracket and rearranging, we have;
3r + 30 = 236 - 200
3r = 236 - 200 - 30
3r = 6
r = 6/3
r = 2
So we now have;
x = 6; y = 4; z = 1; p = 2; q = 8; r = 2
Mobile number is; 9 6 4 1 2 7 8 1 2 3
Read more here; brainly.in/question/24417680?tbs_match=1
