We have this equation:
First, combine both logarithms using the multiplication property and simplify the expression.
![\log[x(x + 99)] = 2](https://tex.z-dn.net/?f=%5Clog%5Bx%28x%20%2B%2099%29%5D%20%3D%202)
![\log[ {x}^{2} + 99x ] = 2](https://tex.z-dn.net/?f=%5Clog%5B%20%7Bx%7D%5E%7B2%7D%20%2B%2099x%20%5D%20%3D%202)
Now, use the definition of logarithm to transform the equation.
Finally, use the quadratic formula to solve the equation.
With this, we can say that the solution set is:
We cannot choose x = -100 as a solution because we cannot have a negative logarithm. The only solution is x = 1.
The situation above described that Jeff added two - thirds of 128 to the flour. The numerical value of (2/3)(128) is 85.33 grams. The recipe says to add only 32 grams of vanilla powder. Hence, Jeff went over the prescribed amount.
To determine the excess amount, subtract 32 from 85.33 which has a numerical value of 53.33 grams.
Answer:
the answer is D
Step-by-step explanation:
Think of the Pythagorean Theorem which states that a^2 + b^2 = c^2. The Pythagorean Identities used in trigonometry are the angle version which can be used to simplify expressions.
HOPE THIS HELPED ;3
