All categories

2 years ago

6 x +4 + 10x - 9 + 8x - 7=

Mathematics

1 answer:

trasher [3.6K]2 years ago

6 0

Answer:

24x - 12

Step-by-step explanation:

6x + 4 + 10x - 9 + 8x - 7

6x + 10x + 8x + 4 - 9 - 7

24x - 12

You might be interested in

Find the measures of the angles in the figure.

Vinvika [58]

Answer:

$120^o,\,120^o,\,60^o,\,\,\,and\,\,\,60^o$

which agrees with the first answer in the list of possible options.

Step-by-step explanation:

We can use the fact that the addition of all four internal angles of a quadrilateral must render $360^o$ . Then we can create the following equation and solve for the unknown "h":

$2h+2h+h+h = 360^o\\6h=360^o\\h=60^o$

Therefore the angles of this quadrilateral are:

$120^o,\,120^o,\,60^o,\,\,\,and\,\,\,60^o$

3 0

3 years ago

Read 2 more answers

If we divide the numerator and denominator of (6/8) by 2, will its value be changed?

astraxan [27]

Answer:

Step-by-step explanation:

6/8 in simplest form is 3/4 but value is still the same so

1. no

3 0

3 years ago

What is the difference? <br><br>( -4x + 3) - (7x -<img src="https://tex.z-dn.net/?f=3x%5E%7B2%7D" id="TexFormula1" title="3x^{2}

trapecia [35]

The answer is 3x^2-19x+1

(-4x+3)-(7x-3x^2-1)
-12x+7x+3x^2+1

Combine like terms:
3x^2+(-12x+-7x)+1
= 3x^2+-19x+1

3 0

3 years ago

7. When dy/dx = (x -6)1/2, what does y equal?

Sergio039 [100]

The answer is below
$\frac{dy}{dx} = \frac{1}{2} (x - 6)$
multiply both sides by dx

$dy = \frac{1}{2} (x - 6)dx$
integrate both sides of the diffrential

$integral \: dy = integral \: \frac{1}{2} (x - 6)dx$
simplify and integrate to get y alone don't forget to tack on c with your indefinite integral

$y = \frac{x {}^{2} }{4} - 3x + c$

3 0

3 years ago

Please help me no one even bothers to help so plzzzz i BEGGGGGGGGGGG

user100 [1]

Answer:

Here's what I get.

Step-by-step explanation:

When you dilate an object by a scale factor, you multiply its coordinates by the same number.

If the scale factor is 4, the rule is (x, y) ⟶ (4x, 4y)

Your table then becomes

$\begin{array}{lcl}\textbf{Vertices of}& \, & \textbf{Vertices of}\\\textbf{VWXY}& \, & \textbf{V'W'X'Y'}\\V(-1 ,1) & \quad & V'(-4, 4)\\W(-1, 2) & \quad & W'(-4, 8)\\X(2, -1) & \quad & X'(8 ,-4)\\Y(2, 2) & \quad & Y'(8, 8)\\\end{array}$

The diagram below shows figure VVXY as a green bow-tie and its image V'W'X'Y' in orange.

The scale factor is greater than one, so the dilation is an enlargement.

7 0

3 years ago