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3 years ago

Expressions that are equivalent to 3(5x-2)

Mathematics

1 answer:

anastassius [24]3 years ago

3 0

Answer:

15x-6

Step-by-step explanation:

3(5x-2)

5x(3)-2(3)

<u><em>15x-6</em></u>

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Please answer the problem below.<br><br> ~Thanks = )

RoseWind [281]

Hi GlaxyCraft4991,

Solution:

−12x − 0.4 > 0.2 (36.5x + 80) − 55

−12x − 0.4 > 7.3x − 39

−12x − 0.4 − 7.3x > 7.3x − 39 − 7.3x

−19.3x − 0.4 > −39

−19.3x − 0.4 + 0.4 > −39 + 0.4

−19.3x > −38.6

−19.3x/19.3 > −38.6/19.3

x < 2

Correct Answer:

x < 2

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3 years ago

Jon paid $20 towards the cost of an $80 sweater. Write a numeric equation to show how much he still owes on the sweater.

Tju [1.3M]

Answer:

$80 - $20 = $60 left.

Step-by-step explanation:

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3 years ago

What is the best measure of center for this data set?

jenyasd209 [6]

I believe the answer to your question is b.

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2 years ago

What is the answer to this question I can’t work it out Ni=n02(yi-yo)/t2

mr_godi [17]

Changing the subject of an equation involves solving for another variable in the equation

The equation of t is $t=\frac{\sqrt{y_i-y_o}}{N}$

<h3>How to change the subject of the equation</h3>

The equation is given as:

$N=\sqrt[2]{\frac{y_i-y_o}{t^2}}$

Rewrite the equation as:

$N=\sqrt{\frac{y_i-y_o}{t^2}}$

Evaluate the square root of t^2

$N=\frac{\sqrt{y_i-y_o}}{t}$

Multiply both sides by t

$Nt=\sqrt{y_i-y_o}$

Make t the subject, in the above equation

$t=\frac{\sqrt{y_i-y_o}}{N}$

Hence, the equation of t is $t=\frac{\sqrt{y_i-y_o}}{N}$

Read more about subject of formula at:

brainly.com/question/657646

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2 years ago

What is the best way to control expenses?

bagirrra123 [75]

Answer:

buying things that you really like

or setting and sticking to a budget

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3 years ago

Read 2 more answers