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erma4kov [3.2K]
3 years ago
7

Expressions that are equivalent to 3(5x-2)

Mathematics
1 answer:
anastassius [24]3 years ago
3 0

Answer:

15x-6

Step-by-step explanation:

3(5x-2)

5x(3)-2(3)

<u><em>15x-6</em></u>

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Find four consecutive positive integers such that the product of the first and fourth is four less than twice the first multipli
r-ruslan [8.4K]
Four consecutive integers... n, n+1, n+2, n+3.

The product of the 1st and 4th is four less than twice the 1st multiplied by the 4th.

n(n+3)=2n(n+3)-4  perform indicated multiplications...

n^2+3n=2n^2+6n-4  subtract n^2 from both sides

3n=n^2+6n-4  subtract 3n from both sides

n^2+3n-4=0  factor

n^2-n+4n-4=0

n(n-1)+4(n-1)=0

(n+4)(n-1)=0, and since n>0

n=1

So the four numbers are 1, 2, 3, 4

check...

1(4)=2(1)4-4

4=8-4

4=4
3 0
3 years ago
Madeline was completing the square and her work is shown below. Identify the line where she made her mistake.. . f(x) = 3x^2 + 6
MAVERICK [17]
In completing the square, the first step is to factor out the first and second term so that the factor (x+a) is highlighted. This is seen in line 1. However, in line 2, the subtracted value should be 3 so as to compensate for the added value. This affects then line 3 as well. The answer is line 2.
8 0
3 years ago
Read 2 more answers
What is the total number of common tangents that can be drawn to the circles
Alexxx [7]

The total number of common tangents that can be drawn to the circles is 2.

<h3>What is a tangent?</h3>

A tangent serves as  line that touches the circle at a single point  whereby the  point where tangent meets the circle is the tangency.

A tangent to a circle can be described as the straight line  that touches the circle at only one point.

Therefore, from the definition, The total number of common tangents that can be drawn to the circles is 2.

Read more on the tangent here:

brainly.com/question/12926708

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6 0
1 year ago
What is the sum?<br> 8+(-12)<br> -20<br> -4<br> 4<br> 20
matrenka [14]

Answer:

-4

Step-by-step explanation:

5 0
3 years ago
What are expressions for MN and LN? Hint Construct the altitude from M to LN.
Nikitich [7]

The question is missing the figure. So, it is in the atachment.

Answer: MN = x\sqrt{2}  LN = \frac{x}{2}.(\sqrt{2} + \sqrt{6} )

Step-by-step explanation: The first figure in the attachment is the figure of the question. The second figure is a way to respond this question by tracing the altitude from M to LN as suggested. When an altitude is drawn, it forms a 90° angle with the base, as shown in the drawing. To determine the other angle, you have to remember that all internal angles of a triangle sums up to 180°.

For the triangle <u>on the left</u> of the altitude:

45+90+angle=180

angle = 45

For the triangle <u>on the right</u>:

30+90+angle=180

angle = 60

With the angles, use the Law of Sines, which is relates sides and angles, as follows:

\frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

For MN:

\frac{x}{sin(30)} = \frac{MN}{sin(45)}

MN = \frac{x.sen(45)}{sen(30)}

MN = x\sqrt{2}

For LN:

\frac{LN}{sen(105)} =\frac{x}{sin(30)}

LN = \frac{x.sin(105)}{sin(30)}

We can determine sin (105) as:

sin(105) = sin(45+60)

sin(105) = sin(45)cos(60) + cos(45)sin(60)

sin(105) = \frac{\sqrt{2} }{2}.\frac{1}{2} + \frac{\sqrt{2} }{2}.\frac{\sqrt{3} }{2}

sin(105) = \frac{\sqrt{2} }{4} + \frac{\sqrt{6} }{4}

LN = \frac{x.sin(105)}{sin(30)}

LN = x.(\frac{\sqrt{2} }{4} + \frac{\sqrt{6} }{4}  ) .2

LN = \frac{x}{2}.(\sqrt{2} + \sqrt{6} )

The expressions for:

MN = x\sqrt{2}

LN = \frac{x}{2}.(\sqrt{2} + \sqrt{6} )

6 0
3 years ago
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