keeping in mind that when the logarithm base is omitted, the base 10 is assumed.
![\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(x)=2\implies \log_{10}(x)=2\implies 10^2=x\implies 100=x](https://tex.z-dn.net/?f=%5Ctextit%7Bexponential%20form%20of%20a%20logarithm%7D%20%5C%5C%5C%5C%20%5Clog_a%28b%29%3Dy%20%5Cqquad%20%5Cimplies%20%5Cqquad%20a%5Ey%3D%20b%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Clog%28x%29%3D2%5Cimplies%20%5Clog_%7B10%7D%28x%29%3D2%5Cimplies%2010%5E2%3Dx%5Cimplies%20100%3Dx)
Answer:
The median is 2
Step-by-step explanation:
Here, we want to get the median for the number of pencils
Firstly, we have to write out the numbers that form the box plot ; we have this as;
1,1,1,2,2,2,2,3,3,5
the median is sum of the 5th and 6th term divided by 2
The 5th term is 2
The 6th term is 2
So the median is;
(2 + 2)/2
= 4/2 = 2
Answer:
The answers would be as follows:
3
3
1
1
Step-by-step explanation:
We can tell that the first two have an infinite number of solutions because when we try to solve, we get a true statement. The first one is done for you below.
-6x + 7 = -6x + 7 ------> Add 6x to both sides
7 = 7 (TRUE STATEMENT)
We can tell the next two have no solution due to the fact that they develop a false statement when trying to solve.
-3x + 7 = 3x + 7 ----> Subtract 7 from both sides
-3x = 3x ---> Divide by 3
-x = x (UNTRUE STATEMENT)
