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myrzilka [38]
3 years ago
12

John mows 3 of his neighbors yards for $20 a yard. How much money did he make?

Mathematics
2 answers:
aksik [14]3 years ago
8 0

Answer:

60

Step-by-step explanation:

Masja [62]3 years ago
3 0

Answer:

The answer is $60

Step-by-step explanation:

If each yard earns John $20, and John cuts 3 yards, then John earns $60.

3 • 20 = 60

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A machine is designed to fill 16-ounce bottles of shampoo. When the machine is working properly, the amount poured into the bott
DiKsa [7]

Answer:

Between 15.95 ounces and 16.15 ounces.

Step-by-step explanation:

We have the following value m, being the mean, sd, being the standard deviation and n, the sample size:

m = 16.05

sd = 0.1005

n = 4

We apply the formula of this case, which would be:

m + - 2 * sd / (n ^ 1/2)

In this way we create a range, replacing we have:

16.05 + 2 * 0.1005 / (4 ^ 1/2) = 16.1505

16.05 - 2 * 0.1005 / (4 ^ 1/2) = 15.9495

Which means that 95% of all samples are between 15.95 ounces and 16.15 ounces.

4 0
3 years ago
There are 100 people in a sport centre.
sleet_krkn [62]

By definition of complement,

Pr[not P | G and T] = 1 - Pr[P | G and T]

and by definition of conditional probability,

Pr[not P | G and T] = 1 - Pr[P and G and T] / Pr[G and T]

Pr[not P | G and T] = 1 - (16/100) / (33/100)

Pr[not P | G and T] = 1 - 16/33

Pr[not P | G and T] = 17/33

4 0
3 years ago
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
Suppose that f(x)=x^2 and g(x)=-1/4(x+7)^2. Which statement best compares the graph of g(x) with the graph of f(x)?
wolverine [178]

Answer:

Both of these graphs are quadratics. They both form a parabola opening up

Step-by-step explanation:

The only difference between g(x) and f(x) is that g(x) is moved to the left 7 unit and has a horizontal stretch of 1/4

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B2%7D%2B2%2B%3D-2%5C%5C" id="TexFormula1" title="\frac{x}{2}+2+=-2\\" alt="\fr
expeople1 [14]
-8 is your answer so x=-8
5 0
3 years ago
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