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mariarad [96]
3 years ago
10

Write 2/5 X 3/7 in simplest form​ brainliest if correct

Mathematics
2 answers:
stich3 [128]3 years ago
5 0

Answer:

6/35

Step-by-step explanation:

2/5x3/7

Multiply Numerators and Denominators

= 6/35

You can't further simplify so the answer is 6/35.

Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

6/35

Step-by-step explanation:

hope this helps, would consider downloading photomath

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What is the period of y = 3cot(4x - 3pi)
Lorico [155]
4x = 2π when x = π/2

The period is π/2.
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3 years ago
Elsa runs 7 miles in 80 minutes. At the same rate, how many miles would she run in 64 minutes?
charle [14.2K]

Heather runs 7 miles in 80 minutes.

At the same rate, how many miles would she run in 64 minutes?

Let x represent miles would she run in 64 minutes?

Question Sets Up the Proportion

7/80= x/63    |Cross Multiplying to solve for x

     x = 7*64/80

     x = 5.6mi

Hope this helps!

7 0
3 years ago
What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br> x =
irinina [24]

4x-10+5x-22+3x+2=180

So x=35/2 or 17.5

8 0
3 years ago
Read 2 more answers
$4 is what percent of $50? Round to the nearest tenth if necessary?
Assoli18 [71]

Answer

8 %( When we round off to the neaerest tenths we get 10%)

Step-by-step explanation

4/50*100

=4*2

=8%

6 0
3 years ago
Need answer to 4 and 5
algol13

Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $ g_n  = 2 . 3^{n - 1} $

To find the first term, substitute n = 1.

Therefore, $ g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1  $ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3 $ = 6

$ g_3 =  2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9 $ = 18

$ g_4 = 2 . 3^{4  - 1} = 2 . 3^{3} = 2 . 27 $ = 54

$ g_5 =  2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81 $ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $ t_n = \frac{2}{3}t_{n - 1} $

$ t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1  = \frac{2}{3}6 $ = 4

$ t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3} $

$ t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9} $

$ t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27} $

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

8 0
3 years ago
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