Question

a1" title="\left \{ {{5x-3y=-8} \atop {xy=12}} \right." alt="\left \{ {{5x-3y=-8} \atop {xy=12}} \right." align="absmiddle" class="latex-formula">
I don't understand the equation, please someone explain me how to resolve.

Answer 1

Answer:

$\left \{ {{5x-3y=-8} \atop {xy=12}} \right.\\\\\left \{ {{5x=3y-8} \atop {xy=12}} \right.\\\\\left \{ {{5x=3y-8} \atop {5xy=60}} \right.\\\\\left \{ {{5x=3y-8} \atop {(3y-8)y=60}} \right.\\\\\left \{ {{5x=3y-8} \atop {3y^{2}-8y -60=0}} \right.\\\\\left \{ {{5x=3y-8} \atop {3y^{2}-18y+10y-60 =0}} \right.\\\\\\\left \{ {{5x=3y-8} \atop {3y(y-6)+10(y-6)=0}} \right.\\\\\left \{ {{5x=3y-8} \atop {(3y+10)(y-6)=0}} \right.$

<=> 5x = 3y - 8

     3y + 10 = 0 or y - 6 = 0

<=> 5x = 3y - 8

     y = -10/3 or y = 6

+) with y = -10/3 => 5x = -10 - 8 <=> 5x  = -18 <=> x = -3.6

+) with y = 6 => 5x = 3.6 - 10 = 8 <=> x = 8/5 = 1.6

Step-by-step explanation: