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vekshin1
3 years ago
10

Why is it important to solve an equation for a specific variable

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
3 0
It's important because you need to find certain numbers for different causes and also it's important because the question that you're dealing with might also ask for only one variable 

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Need help ASAP!!!!!!!
Temka [501]

D

Step-by-step explanation:

2/6 is litterally right there cause it has seven lines and tge 0 doesnt count

3 0
2 years ago
Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a
Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force (\vec F), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

\vec F =  \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right) (1)

Vector (ordered pair - polar form)

\vec F = \left(\|\vec F\|, \theta\right)

Sum of vectorial components (linear combination)

\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j} (2)

Where:

\|\vec F\| - Norm of the vector force, in newtons.

\theta - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

\hat{i}, \hat{j} - Orthogonal axes, no unit.

If we know that \|\vec F\| = 30\,lbf and \theta = 25^{\circ}, then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

8 0
2 years ago
The answer and explanation to question 1
xxMikexx [17]

Answer:

20, 31, 33, 35, 55, 57, 58, 59, 72, 73, 79, 86, 87, 88

Step-by-step explanation:

The data set is split by digit. So 2|0 becomes 20. 5|5 becomes 55. Using this method, the data set is

20, 31, 33, 35, 55, 57, 58, 59, 72, 73, 79, 86, 87, 88

7 0
3 years ago
Suppose there are 21 students in your class if the draws two names at random
Gala2k [10]

Answer:

2/21 is the most logical answer

Step-by-step explanation:

4 0
2 years ago
Camryn practices the trumpet every 11^\text{th}11
Snowcat [4.5K]

Answer:

in 33 days

Step-by-step explanation:

Trumpet practice is every 11 days. Flute practice is every 3 days.

You need the Least Common Multiple (the LCM) of the two numbers, 3 and 11.

Since 3 and 11 are prime, the LCM of 3 and 11 is their product.

LCM = 3 * 11 = 33

Answer: in 33 days

You can also solve this by listing multiples of 3 and 11 until you find the smallest number that is a multiple of both 3 and 11.

Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, ...

Multiples of 11: 11, 22, 33, 44, ...

The smallest multiple of both 3 and 11 is the smallest number that shows in both lists. It is 33.

4 0
3 years ago
Read 2 more answers
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