Question

What is the solution to the system of equations below? x 3 y = 15 and 4 x 2 y = 30 (6, 3) (3, 6) (7, –6) (–6, 7).

Answer 1

Answer: (6 , 3)

Step-by-step explanation: Given

x + 3y =15 ------- equation 1

4x + 2y = 30 --------- equation 2

x = 15 - 3y

Put value of x in equation 2

4 (15 - 3y) + 2y = 30

60 - 12y + 2y = 30

-10y = -30

divide by '-10' on both sides

y = 3

now, put value of y in equation 1

x + 3(3) = 15

x + 9 = 15

x = 15 - 9

x =  6

So , (x , y) = (6 , 3)