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it is given that the standard deviation 0.8, so we can use the normal distribution critical value for the 95% confidence interval.
<span>sample mean = 2.36 </span>
<span>standard deviation = 0.8 </span>
<span>standard error of mean = σ / √ n </span>
<span>standard error of mean = 0.8 / √ 50 </span>
<span>se = 0.8/7.0711 </span>
<span>standard error of mean 0.1131 </span>
<span>Confidence interval 2.36-(0.1131)(1.96) </span>
<span>and 2.36+(0.1131)(1.96) </span>
<span>95% confidence interval :(2.14, 2.58) </span>
In order to solve for a nth term in an arithmetic sequence, we use the formula written as:
an = a1 + (n-1)d
where an is the nth term, a1 is the first value in the sequence, n is the term position and d is the common difference.
First, we need to calculate for d from the given values above.
<span>a1 = 38 and a17 = -74
</span>
an = a1 + (n-1)d
-74 = 38 + (17-1)d
d = -7
The 27th term is calculated as follows:
a27 = a1 + (n-1)d
a27= 38 + (27-1)(-7)
a27 = -144 -----------> OPTION D
Approximately 65.94 if calculated with pi only to the 3rd digit.
X= - 4/5
Answer for number 10