There are NO SOLUTIONS.
Substitute the first equation for y in the second equation. You can see it does not work. 6 does not equal 8. Therefore there are no solutions.
First simplify <span>t^2-t-12, which becomes (t-4)(t+3)
now you can rewrite the expression as one term; (t-4)(t+3)(t+1)/(t+1)(t+3)
cancel out (t+3) and (t+1) which leaves the answer as (t-4)</span>
Answer:
dx. = yex ⇒ dy y. ∫. = x ... 2 xx dx. ∫. , i.e. yx = 4. 4 x c. +. Hence y = 3. 4 x c x.
Formula= (y2-y1)/ (x2-x1)
(-5 - -1) / (-2 - -4)
(-4) / (2) = -2
q8 is C
(-3 - -3) / (8 - 4)
(0) / (4) = 0
q12 is D
I think it’s 3 not sure tho because i forgot most things about it