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3 years ago

When rolling a standard number cube: P(3 and then even)?

Mathematics

1 answer:

Fynjy0 [20]3 years ago

8 0

B could be the only answer

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Please help Use the expression 8a + 16c.

alexdok [17]

Answer:

C 89a + 2c)

Step-by-step explanation:

The largest factor of both 8 and 16 is 8. So, 8 = GCF

factor out an 8 and you get 8(a + 2c)

To check if you are correct, multiply and see if you get what you started with.

3 0

3 years ago

Read 2 more answers

Distance between -6, -4, and -9, 0 on a coordinate plane

dangina [55]

Answer:

hdjixuwowiuejeutst81+€+"77#8"72782+"6€(3;+€#+:"8+#-7_61+*9*#7€9"+€9€71923791-499€9782833927258160094720&72700828292792(#+€928€+9#+#827€-92727€!#}¥

3 0

3 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

IF U CAN READ WHAT IT SAYS uu JUST MIGHT GET A BRAINLIEST

Nutka1998 [239]

Answer:

hmmm...

Step-by-step explanation:

This looks like...

"jnxxmppoihuueitsdehbxexdnjussheyetyyuuhggfffwspiritualdjjdmsmmsmyra."

YES!

(lol)

4 0

3 years ago

Need help asap question in picture

Neporo4naja [7]

Answer:

The triangle is a obtuse triangle

Step-by-step explanation:

5 0

3 years ago