When rolling a standard number cube: P(3 and then even)?

Can 12m, 35m and 37m make a right triangle

antoniya [11.8K]

Answer:

YES

Step-by-step explanation:

Explanation:

If this is a right triangle we can then substitute the sides of the triangle (12 and 35) and the hypotenuse (37) into the Pythagoras Theorem and the two sides of the equation will be equal. If this is not a right triangle the two sides of the equation will not be equal.

The Pythagoras Theorem is

a

2

+

b

2

=

c

2

Substituting we get:

12

2

+

35

2

=

37

2

12

⋅

12

+

35

⋅

35

=

37

⋅

37

144

+

1225

=

1369

=

1369

Because these are equal this is a right triangle.

3 0

2 years ago

Read 2 more answers

Convert the following to standard form y=2/5 x - 1/3

Afina-wow [57]

Given :-

y = 2/5x - 1/3

To Find :-

To convert the given equation into standard form.

Solution :-

As we know that the standard form of the line is ,

$\sf\longrightarrow$ ax + by + c = 0

So the given equation is ,

$\sf\longrightarrow$ y = 2/5x -1/3

$\sf\longrightarrow$ y = 6x - 5/15

$\sf\longrightarrow$ 15y = 6x - 5

$\sf\longrightarrow$ 6x -15y -5 = 0

Hence the required equation of the line is 6x -15y-5=0.

8 0

2 years ago

Use the quadratic formula to find the solutions to the equation x^2-3x+1=0

Gnom [1K]

Answer:

$x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}$

Step-by-step explanation:

Using:

$x=\frac{-b+-\sqrt{b^{2}-4*a*c} }{2*a}$

we will have two solutions.

x^2-3x+1=0

So, a=1 b=-3 c=1

$x_{1}=\frac{+3+\sqrt{-3^{2}-4*1*1} }{2*1}\\\\x_{2}=\frac{+3-\sqrt{-3^{2}-4*1*1} }{2*1}$

We have two solutions:

$x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}$

4 0

3 years ago

Where is 10 in the real number system

7nadin3 [17]

10 / 1 is a rational and which is equal to 10 so 10 is also a rational number

3 0

3 years ago

What are expressions equal to 16a+40

Liula [17]

8a+8a+40
It is equivalent

8 0

3 years ago