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2 years ago

Write the equation it passes through (0,-2) and is perpendicular to the graph of y=5x+7

Mathematics

1 answer:

romanna [79]2 years ago

6 0

Step-by-step explanation:

the line passes through (0,-2) and perpendicular to the graph of y=5x+7.

solution :

the slope = -1/5

the equation :

y+2 = -1/5 (x-0)

y = -1/5x - 2

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-3/6 -2/6 -1/6 0/6 1/6 2/6

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2 years ago

M and m A) -9 C) 0 B) 10 D) -10 A B C С D

Mademuasel [1]

Answer:

Step-by-step explanation:

∠ BSR + ∠ TSB = ∠ TSR , substitute values

2x + 17 + 5x + 15 = 102 , that is

7x + 32 = 102 ( subtract 32 from both sides )

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3 years ago

What is 6/8 written in simplest form

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3 years ago

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What is the measure of angle c

Mars2501 [29]

Answer:

Angle C=35 degrees

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Angle C is an external angle. So, we can use the external angle theorem and get the equation

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3 years ago

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Simplify seven square root of three end root minus four square root of six end root plus square root of forty eight end root min

Cloud [144]

$7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54}$ simplified as $11\sqrt{3}- 7\sqrt{6}$ or $1.909$ .

Step-by-step explanation:

We need to Simplify seven square root of three end root minus four square root of six end root plus square root of forty eight end root minus square root of fifty four. Which is equivalent to $7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54}$ :

$7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54}$

⇒ $7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{44}$

⇒ $7\sqrt{3}- 4\sqrt{6} + \sqrt{16(3)} - \sqrt{9(6)}$

⇒ $7\sqrt{3}- 4\sqrt{6} + 4\sqrt{(3)} - 3\sqrt{(6)}$

⇒ $11\sqrt{3}- 4\sqrt{6}- 3\sqrt{(6)}$

⇒ $11\sqrt{3}- 7\sqrt{6}$

$\sqrt{3} = 1.732 , \sqrt{6} = 2.449$

⇒ $11(1.723)- 7(2.449)$

⇒ $1.909$

Therefore, $7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54}$ simplified as $11\sqrt{3}- 7\sqrt{6}$ or $1.909$ .

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2 years ago