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3 years ago

-6+(-6)+(-6)+(-6)+(-6)+(-6)+[(-3)+(-3)+(-3)+(-3)+(-3)+(-3)]=(-6)(◻) What's the missing number?

Mathematics

2 answers:

Nataly [62]3 years ago

4 0

The missing number is 9. Pretty long equation..

Snezhnost [94]3 years ago

4 0

It ends up being -36+(-18) that added together is -54 divide that by -6 and you get 9.

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Anton [14]

Answer:4

Step-by-step explanation:

f(1)=6(1)+2

g(f(1))=2(8)+4/5

=20/5

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2 years ago

now find the components nx and ny of n⃗ in the tilted coordinate system of part b. express your answer in terms of the length of

saw5 [17]

The components are Nx= Ncosθ and Ny= -Nsinθ

<h3>What is a Vector?</h3>

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Generally, F sinθ is the vertical component and F cosθ is the horizontal component,

Now, from the diagram the horizontal component of vector 'r' is

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Learn more about vectors here:

brainly.com/question/1600633

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2 years ago

The saucer for Aisha's teacup has a diameter of 6 inches. What is the saucer's radius?

Aleonysh [2.5K]

I think its 6 but im not sure to be exactly right

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2 years ago

The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth

MAXImum [283]

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

$\twoheadrightarrow \quad\sf{ Length =2(Width)-5}$

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

$\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\$

l denotes length
b denotes breadth

$\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\$

$\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{60= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\$

$\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\$

Now, finding the length. According to the question,

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

$\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}$

$\twoheadrightarrow \quad\sf{ \ell=20-5\; m}$

$\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\$

Therefore, length and breadth of the rectangle is 15 m and 10 m. 

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3 years ago

Is the height of an equilateral triangle the same as the sides?

Hoochie [10]

No,
although all the sides are the same length on an equilateral triangle the height is calculated by a straight perpendicular line at the mid point of the base.

The sides are not perpendicular with the base and are angled outwards

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2 years ago