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3 years ago

-6+(-6)+(-6)+(-6)+(-6)+(-6)+[(-3)+(-3)+(-3)+(-3)+(-3)+(-3)]=(-6)(◻) What's the missing number?

Mathematics

2 answers:

Nataly [62]3 years ago

4 0

The missing number is 9. Pretty long equation..

Snezhnost [94]3 years ago

4 0

It ends up being -36+(-18) that added together is -54 divide that by -6 and you get 9.

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Consider a series circuit consisting of a resistor of R ohms, an inductor of L henries, and variable voltage source of V(t) volt

ser-zykov [4K]

Answer:

$I(t)=\frac{1}{3}(1-e^{-30t})$

Step-by-step explanation:

We are given that

$\frac{dI}{dt}+\frac{R}{L}I=\frac{V(t)}{L}$

R=150 ohm

L=5 H

V(t)=10 V

$P=\frac{R}{L}=\frac{150}{5}=30$

$I.F=e^{\int Pdt}=e^{\int 30 dt}=e^{30 t}$

$I(t)\times I.F=\int e^{30 t}\times 10 dt+C$

$I(t)\times e^{30 t}=\frac{10}{30}e^{30 t}+C$

$I(t)=\frac{1}{3}+Ce^{-30 t}$

I(0)=0

Substitute t=0

$0=\frac{1}{3}+C$

$C=-\frac{1}{3}$

Substitute the values

$I(t)=\frac{1}{3}-\frac{1}{3}e^{-30 t}$

$I(t)=\frac{1}{3}(1-e^{-30t})$

5 0

3 years ago

B is the midpoint of A . If AB = x+5 and BC =2x-11, find the measure of AB

nignag [31]

If B is the midpoint of AC, then AB = BC.

We have AB = x + 5 and BC = 2x - 11.

Therefore we have the equation:

x + 5 = 2x - 11 <em>subtract 5 from both sides</em>

x = 2x - 16 <em>subtract 2x from both sides</em>

-x = -16 <em>change the signs</em>

x = 16

Put the value of x to the expression x + 5:

AB = 16 + 5 = 21

<h3>Answer: AB = 21</h3>

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Answer:

28.27433

Step-by-step explanation:

using the pie radius squared formula

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Step-by-step explanation:

Given

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Lastly,

$x = 180 - 126 \\ = 54(angles \: on \: the \: same \: straight \: line \: and \: corresponding \: angles)$

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2 years ago

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Marysya12 [62]

Answer:

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