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Alekssandra [29.7K]
3 years ago
6

Please help no one is answering my questions!

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
5 0

Answer: x - 4

The missing dimension of the prism is A

because the volume of the rectangular prism equals the product of the sides, we have:

V = (x - 1)(x - 3)A

but V = x³ - 8x² + 19x - 12

=> x³ - 8x² + 19x - 12 = (x - 1 )(x - 3)A

⇔ x²(x - 1) - 7x(x - 1) + 12(x - 1) = (x - 1)(x - 3)A

⇔ (x² - 7x + 12)(x - 1) = (x - 1)(x - 3)A

⇔ (x² - 3x - 4x + 12)(x - 1) = (x - 1)(x - 3)A

⇔ (x - 3)(x - 4)(x - 1) = (x - 1)(x - 3)A

⇒ A = x - 4

Step-by-step explanation:

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Answer:

Option c

Step-by-step explanation:

A system of equations are given to us. And we need to solve them . The given system is

\begin{cases} y = 2x - 3\dots 1 \\ y = x^2 - 3\dots 2 \end{cases}

We numbered the equations here . Now put the value of equation 1 in equation 2 that is substituting y = 2x - 3 in eq. 2 .

\implies y = x^2 - 3 \\\\\implies 2x - 3 = x^2 - 3 \\\\\implies x^2 - 2x = 0 \\\\\implies x(x-2) = 0 \\\\\implies\red{ x = 0 , 2 }

We got two values of x as 0 & 2 . Alternatively substituting these values we have ,

\implies y = 2 x - 3 \\\\\implies y = 2(0)-3 \qquad or \qquad y = 2(2)-3 \\\\\implies y = 0-3 \qquad or \qquad 4 - 3 \\\\\implies \red{ y = -3 , 1 }

Thefore the required answer is ,

\red{Option\:c} \begin{cases} (0,-3) \\ (2,1) \end{cases}

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