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3 years ago

What is the reason for an outlier in a graph?

1 answer:

7 0

It is sometimes called an extreme value. When you graph an outlier, it will appear not to fit the pattern of the graph. Some outliers are due to mistakes (for example, writing down 50 instead of 500) while others may indicate that something unusual is happening

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Greg has four different colored cards in a box. Yellow, red, blue, and green. He randomly selects one card, records the color, a

Veronika [31]

Answer:

He should expect to select 75 yellow cards.

Step-by-step explanation:

Since there is replacement, for each trial, we have:

1 yellow card

1 red card

1 blue card

1 green card.

If Greg does this 300 times, how many yellow cards should he expect to select?

Each trial, there are 4 cards, one of which is yellow. So 1/4 = 0.25 probability of selecting a yellow card.

Over 300 trials

0.25*300 = 75

He should expect to select 75 yellow cards.

6 0

3 years ago

In each box is a step in the process of solving a max/min problem like the one in Question 8. Number these steps in order (1-8)

Dmitriy789 [7]

Answer:

The steps are numbered below

Step-by-step explanation:

To solve a maximum/minimum problem, the steps are as follows.

1. Make a drawing.

2. Assign variables to quantities that change.

3. Identify and write down a formula for the quantity that is being optimized.

4. Identify the endpoints, that is, the domain of the function being optimized.

5. Identify the constraint equation.

6. Use the constraint equation to write a new formula for the quantity being optimized that is a function of one variable.

7. Find the derivative and then the critical points of the function being optimized.

8. Evaluate the y-values of the critical points and endpoints by plugging them into the function being optimized. The largest y- value is the global maximum, and the smallest y-value is the global minimum.

8 0

3 years ago

Write the slope-intercept form of the line that has a slope of 2 and intersects the line, 2X - 3Y = 6 at X = 3

Shtirlitz [24]

so these two lines intersect at x = 3 hmmmm what's the y-coordinate of the second line at that point?

$\bf 2x-3y=6\implies \stackrel{\textit{using x = 3}}{2(3)-3y=6}\implies 6-3y=6\implies -3y=0\implies y=0$

so the y-coordinate of that second line is 0, so the point there is (3, 0) then.

so the first line is, a line that has a slope of 2 and passes through (3, 0).

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{0})~\hspace{10em} slope = m\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=2(x-3)\implies y=2x-6$

6 0

3 years ago

Can you answer this and explain it please! for 100 points

pashok25 [27]

Answer:

D) -12

Step-by-step explanation:

$3(x-4)+(2-x)-x^2$

Replace X With 5

$3(5-4)+(2)(5)-5^2$

$=-12$

I Hope This Helps

Please Mark Me As Brainliest :)

6 0

2 years ago

In July, a new endoscopy and electrophysiological lab are opening up. It is projected 60 endoscopies and 5 EP studies will be pe

kupik [55]

Answer:

The number of FTE needed to be hired to cover the additional procedures per 7.5 day work is:

= 1.

Step-by-step explanation:

a) Data and Calculations:

Endoscopies EP Studies Total

Projected number of studies 60 5 65

Time in minutes for per study 5 15

Total time required (in minutes) 300 75 375

Full-time Employee (FTE) works 7.5-hour day or 450 minutes (7.5 * 60) per day.

b)The number of full-time employees (FTE) needed to be hired to cover the additional procedures per 7.5-day work is 1. The FTE has 450 minutes available for the additional procedures. She will only require 375 minutes. Therefore, she has extra (idle) time of 75 (450 - 375) minutes per workday.

4 0

3 years ago