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const2013 [10]
3 years ago
10

2. A change in velocity (speed and/or direction) is... *

Chemistry
2 answers:
zepelin [54]3 years ago
8 0
Acceleration cause that is a magnitude
jek_recluse [69]3 years ago
7 0
The answer is acceleration
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What is the theoretical yield of NaBr
dolphi86 [110]

The theoretical yield of NaBr given that 2.36 moles of FeBr₃ reacts is 7.08 moles

<h3>Balanced equation </h3>

2FeBr₃ + 3Na₂S → Fе₂S₃ + 6NaBr

From the balanced equation above,

2 moles FeBr₃ reacted to produce 6 moles of NaBr

<h3>How to determine the theoretical yield of NaBr</h3>

From the balanced equation above,

2 moles FeBr₃ reacted to produce 6 moles of NaBr

Therefore,

2.36 moles FeBr₃ will react to produce = (2.36 × 6) / 2 = 7.08 moles of NaBr

Therefore,

Thus, the theoretical yield of NaBr is 7.08 moles

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

7 0
2 years ago
The first-order rate constant for the reaction of methyl chloride (CH3Cl) with water to produce methanol (CH3OH) and hydrochlori
Dvinal [7]

Answer:

K(48.5°C) = 1.017 E-8 s-1

Explanation:

  • CH3Cl + H2O → CH3OH + HCl

at T1 = 25°C (298 K) ⇒ K1 = 3.32 E-10 s-1

at T2 = 48.5°C (321.5 K) ⇒ K2 = ?

Arrhenius eq:

  • K(T) = A e∧(-Ea/RT)
  • Ln K = Ln(A) - [(Ea/R)(1/T)]

∴ A: frecuency factor

∴ R = 8.314 E-3 KJ/K.mol

⇒ Ln K1 = Ln(A) - [Ea/R)*(1/T1)]..........(1)

⇒ Ln K2 = Ln(A) - [(Ea/R)*(1/T2)].............(2)

(1)/(2):

⇒ Ln (K1/K2) = (Ea/R)* (1/T2-1/T1)

⇒ Ln (K1/K2) = (116 KJ/mol/8.3134 E-3 KJ/K.mol)*(1/321.5 K - 1/298 K)

⇒ Ln (K1/K2) = (13952.37 K)*(- 2.453 E-4 K-1)

⇒ Ln (K1/K2) = - 3.422

⇒ K1/K2 = e∧(-3.422)

⇒ (3.32 E-10 s-1)/K2 = 0.0326

⇒ K2 = (3.32 E-10 s-1)/0.0326

⇒ K2 = 1.017 E-8 s-1

7 0
4 years ago
What is the systematic name of Mg(NO3)2?A) Manganese nitrite.B) Magnesium nitrite.C) Magnesium nitrate.D) Manganese nitrate.
olganol [36]
Mg is magnesium. NO3 is nitrate. This gives you magnesium nitrate as an answer.
6 0
3 years ago
2. How many of the heavier elements do we know of?
Pavel [41]
A heavy element is an element with an atomic number greater than 92. The first heavy element is neptunium (Np), which has an atomic number of 93. Some heavy elements are produced in reactors, and some are produced artificially in cyclotron experiments.
4 0
3 years ago
Write the ions present in a solution of na2co3. express your answers as chemical formulas separated by a comma. offset subscript
Andrei [34K]
Na₂CO₃ → 2Na⁺ + CO₃²⁻

CO₃²⁻ + H₂O ⇄ HCO₃⁻ + OH⁻

HCO₃⁻ + H₂O ⇄ CO₂·H₂O + OH⁻

Na⁺, CO₃²⁻, HCO₃⁻, OH⁻
4 0
4 years ago
Read 2 more answers
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