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The correct answer is
Energy of electrons depends on light’s frequency, not intensity.
As per photoelectric effect, if we incident a light on metal surface it will results into emission of electron from it
if we increase the number of photons the number of electrons will increase however if we increase the frequency the number of photons will not increase
While if we increase frequency the energy of electrons will increase as
Energy of photon = Work function of metal + kinetic energy of electrons
This answer is C hope this helped
First find the names of the acids end in “acid”. Acid formulas have one of these forms: HX(aq) or HaXbOc then find the Ionic compounds that contain hydroxide. (OH-) , carbonate (CO32-) , or hydrogen carbonate (HCO3-) anions are basic.
The anode is the electrode where the oxidation occurs.
Cathode is the electrode where the reducction occurs.
Equations:
Mn(2+) + 2e- ---> Mn(s) Eo = - 1.18 V
2Fe(3+) + 2e- ----> 2 Fe(2+) 2Eo = + 1.54 V
The electrons flow from the electrode with the lower Eo to the electrode with the higher Eo yielding to a positive voltage.
Eo = 1.54 V - (- 1.18) = 1.54 + 1.18 = 2.72
Answer: 2.72 V
