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Dafna1 [17]
3 years ago
8

I only need help in the bottom section? Please someone help me please?

Chemistry
2 answers:
kherson [118]3 years ago
4 0
Energy in the nucleus of an atom of uranium: Nuclear energy
Energy of a moving object: Kinetic Energy 
Energy stored in chemical bonds: Potential Energy
Energy emitted from light bulb: Radiant Energy
Energy in a battery: Stored Energy
Energy in our food: Chemical Energy
Energy emitted from a radio: Electromagnetic Energy
Energy affected by mass and speed: Kinetic Energy
Energy affected by position and condition: Potential Energy
Energy from our star that some homes use for electricity: Radiant Energy
I hope this was found helpful!
I was happy to assist you with your Homework :)
jek_recluse [69]3 years ago
3 0
I can't see it can you please send me a picture and I will love to help you.
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If 2.0 ml of 6.0m hcl is used to make a 500.0-ml aqueous solution, what is the molarity of the dilute solution?
svp [43]
Make sure that you understand what they are asking you from this question, as it can be confusing, but the solution is quite simple. They are stating that they want you to calculate the final concentration of 6.0M HCl once a dilution has been made from 2.0 mL to 500.0 mL. They have given us three values, the initial concentration, initial volume and the final volume. So, we are able to employ the following equation:

C1V1 = C2V2
(6.0M)(2.0mL) = C2(500.0mL)
Therefore, the final concentration, C2 = 0.024M.
4 0
3 years ago
Read 2 more answers
A) What is the maximum number of grams of nickel bromide that can be produced from the reaction of 67.8 g of nickel with 37.3 g
svetoff [14.1K]

Answer:

The answer to your question is a) 51.07 g of NiBr₂   b) Nickel, 54 g

Explanation:

Data

mass of NiBr₂ = ?

mass if Ni = 67.8 g

mass of Br = 37.3 g

Balanced chemical reaction

                Ni  +  Br₂   ⇒   NiBr₂

Process

1.- Find the atomic mass of the reactants and the molar mass of the product

Ni = 59 g

Br = 79.9 x 2 = 159.8 g

NiBr₂ = 59 + 159.8 = 218.8 g

2.- Find the limiting reactant

theoretical yield  Ni/Br₂ = 59/159.8 = 0.369

experimental yield Ni/Br₂ = 67.8/37.3 = 1.81

The limiting reactant is Bromine because the experimental yield was lower than the theoretical yield.

3.- Calculate the mass of NiBr₂

                    159.8 g of Br₂ --------------- 218.8 g of NiBr₂

                      37.3 g of Br₂ --------------  x

                          x = (37.3 x 218.8) / 159.8

                          x = 8161.24/159.8

                          x = 51.07 g of NiBr₂

4.- Find the excess reactant

The excess reactant is Nickel

                59 g of Ni ---------------- 159.8 g of Br₂

                  x               ----------------  37.3 g of Br₂

                            x = (37.3 x 59)/159.8

                            x = 2200.7/159.8

                            x = 13.77 g of Ni

Excess Ni = 67.8 - 13.77

                 = 54 g

5 0
3 years ago
Coffee is decaffeinated industrially using supercritical (sc) CO2. One advantage to using scCO2 is that the polarity of the supe
koban [17]

Answer:

Yes

Explanation:

A supercritical fluid has good properties for both liquid and as for extraction properties, the advantages then include:

  • The fact that it has a lower viscosity than liquid CO2 allowing it to move through and around coffee beans more thoroughly with creating back pressure
  • Its density is comparable to that of liquid CO2 meaning there is much CO2 per litre as there is liquid form making it more efficient
  • It has a higher diffusivity than liquid CO2 which aids with penetration of the coffee beans on a molecular level

This experiment would not work with tea leaves because they also contain caffeine

6 0
3 years ago
Which layer is the oldest layer? How can you tell? ​
Neporo4naja [7]

Answer:

The principle of superposition states that the oldest rock units are at rock bottom , and therefore the youngest are at the highest . Based on this, layer C is oldest, followed by B and A. So the full sequence of events is as follows: Layer C formed.

Explanation:

6 0
3 years ago
Read 2 more answers
If 14c-labeled uracil is added to the growth medium of cells, what macromolecules will be labeled?
ziro4ka [17]
When there are 14c-lable uracil that are added to the growth medium of cells, the macromolecules that will be labled are RNA. Uracil is a nucleobase that make up the DNA or the RNA. In RNA, uracil binds with other nucleobase (adenine) through hydrogen bonds.
6 0
3 years ago
Read 2 more answers
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