Answer:
The horizontal distance between the parking lot and the launch site is 470 meters
Step-by-step explanation:
Let
x-----> the horizontal distance between the parking lot and the launch site
we know that
The tangent of angle of 12 degrees is equal to divide the altitude of 100 meters by the horizontal distance
so
tan(12°)=100/x
Solve for x
x=100/tan(12°)=470 meters
Answer:
X .
-1 | 2
-11-1
-11-4
0 3
2 1-1
-13
0
0
-4-1
--3 0
-1 2
-1 1
0 3
2-5
0 0
2
2
3
3
A. III
B.IV
C.
D
1\
Step-by-step explanation:
Answer:
∛16
Step-by-step explanation:
2^4/3
2^4 = 16
Then 16^1/3
∛16
The y intercept will be (0,-9) and the x-intercept will be (-3.5, 0)
