<span>THE AREA OF THE ROOM IS :A=4*2.4=9.6 m^2 THICKNESS t=0.30 m DIFFERENCE IN TEMPERATURE dT=18-6=12 q=kAdT/dx=kA*dT/t q=1.3(9.6)(12)/0.30=4992 W=499.2 J/s In 1 hour or 3600 sec P=q*T=(499.2 J/s)(3600 s)=1797120 J=1.8 MJ
1.8MJ OF HEAT FLOWS HTROUGH THE WALL IN ONE HOUR</span>