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alukav5142 [94]
3 years ago
9

What is the solution to the equation? Pls help ASAP

Mathematics
1 answer:
fgiga [73]3 years ago
5 0

Answer: 12 1/2

Step-by-step explanation:

its easy bruh what grade you in this is 6th grade stuff

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G(-4, -8) and H(-15, -3). What is the slope of GH?
Masteriza [31]

Answer:

G(x1,y1)= (-4,-8)

H(x2,y2)=(-15,-3)

Slope = (y2-y1)/(x2-x1)

=(-3-(-8))/ (-15-(-4))

= (-3+8)/(-15+4)

=5/-11

3 0
3 years ago
Rectangle A has a length of 12 and width of 8. Rectangle B has a length of 15 and a width of 10.
navik [9.2K]

Answer:

rectangles are similar figures, thus if scaled copies of each other then the ratios of corresponding sides must be equal

compare ratios of lengths and widths

rectangles A and B

k =  =  ← ratio of lengths

k =  =  ← ratio of widths

scale factors are equivalent, hence rectangle A is a scaled copy of B

rectangles C and B

k =  =  ← ratio of lengths

k =  =  ← ratio of width

scale factors (k ) are not equal, hence C is not a scaled copy of B

rectangles A and C

k =  =  ← ratio of lengths

k =  ← ratio of widths

the scale factors are not equal hence A is not a scaled copy of C

Step-by-step explanation:

6 0
3 years ago
Can someone please help i posted this question already and it got ingored
coldgirl [10]
The answer is C, since the number in the parenthesis represent what is being multiplied every year
3 0
3 years ago
The equation below shows the total volume (V),in cubic units, of 2 identical boxes with each side equal to s units:
mrs_skeptik [129]
A. 21.0 cubic units
2 × 3.5 × 3
8 0
3 years ago
Given the following system of equations: 2x + 6y = 12 4x + 3y = 15 Which action creates an equivalent system that will eliminate
ozzi

Answer:

Multiply the second equation by −2 to get −8x − 6y = −30.

Step-by-step explanation:

{2x + 6y = 12

{4x + 3y = 15

{2x + 6y = 12

{−8x − 6y = −30 >> New Equation

* Doing this will give you <em>additive</em><em> </em><em>inverses</em><em> </em>of −6y and 6y, which result in 0, so they are both ELIMINATED.

** [3, 1] is your solution.

I am joyous to assist you anytime.

6 0
3 years ago
Read 2 more answers
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