Answer:
∠CBJ ≅ ∠ DHG
∠ FJH ≅ ∠ AJB
m∠JAB=75°
m∠JBC=130°
Step-by-step explanation:
Please refer to the image uploaded with this answer.
Here we are given two parallel line C and D and two transverses to them E and G , there by forming a number of angles. Before answering them we must under stand the characteristics of the angles formed by them and the various properties of them. For that please refer to the image attached,
i) we are asked to find the congruent angle to ∠CBJ has a corresponding angle names as ∠ DHG. And corresponding angles are same so ∠CBJ ≅ ∠ DHG
ii) Also ∠ FJH ≅ ∠ AJB , as they are vertically opposite angles and vertically opposite angles are equal.
iii) m∠EFD =75°
m∠EFD ≅ m∠JAB=75° ( corresponding angles )
iv) m∠GHF=130°
m∠GHF=m∠JBC=130° ( corresponding angles )
False test with 10 questions
see the attached figure to better understand the problem
we know that
in the right triangle ABC
cos 56°=AC/AB
where
AC is the adjacent side to angle 56 degrees------> the distance from the surveyor to the building
AB is the hypotenuse-----> 148 ft 2 in
56 degrees------> is the angle of elevation
so
cos 56°=AC/AB---------> solve for AC
AC=AB*cos 56°
AB=148 ft 2 in
convert 2 in to ft
1 ft -----> 12 in
x ft------> 2 in
x=2/12-----> x=0.17 ft
AB=148 ft 2 in-----> 148 ft+0.17 ft------> AB=148.17 ft
AC=AB*cos 56°----> AC=148.17*cos 56°------> AC=82.86 ft
convert 0.86 ft to in
0.86 ft=0.86*12-----> 10.32 in
distance AB=82 ft 10 in
the answer is
the distance from the surveyor to the building is 82 ft 10 in
Answer:
<h2>125 tickets for an adult</h2><h2>and 175 tickets for a student</h2>
Step-by-step explanation:
