Answer:
1813.137 KJ
Step-by-step explanation:
potential energy of the body = mgH
where m is mass in Kg , g= 9.81 m/sec^2 and H= height in m
here m= 1000 kg, g= 9.81 m/s^2 and H= 607 feet = 607×0.305= 185.135 m
hence the potential energy p= 1000×9.81×185.135= 1813137.2 J
= 1813.137 KJ
hence the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass as 1000 kg is = 1813.137 KJ
Answer:

Step-by-step explanation:


Answer:
The answers are in solutions.
Step-by-step explanation:
- Four businessmen invested a sum of Rs. 250,000 in the ratio of 3:5:7:10 to start a new business.
(i) The amount invested by each businessman is;
<u>1^st businessman invested:</u>
<u />
Rs. 30,000
<u>2^nd businessman invested:</u>
<u />
<u />
= Rs. 50,000
<u>3^rd businessman invested:</u>
<u />
<u />
= Rs. 70,000
<u>4^th businessman invested:</u>
<u />
= Rs. 100,000
- If they gained Rs. 50,000
(ii) The profit each one of them got is;
<u>1^st businessman got:</u>
<u />
<u />
= Rs. 6,000
<u>2^nd businessman got:</u>
<u />
<u />
= Rs. 10,000
<u>3^rd businessman got:</u>
<u />
<u />
= Rs. 14,000
<u>4^th businessman got:</u>
= Rs. 20,000
I think it might be 11x-8
I'm really sorry if that's wrong